Question

Difficulty: HardSequential Processes and State Transitions

A subscription service evaluates customer activity over a three-month period (k=1,2,3k = 1, 2, 3). At the end of each month kk, a customer's total loyalty points PkP_k update based on their points from the previous month Pk1P_{k-1} and the net points earned during month kk (Δk\Delta_k), according to the state transition rule:

Pk=0.8×Pk1+ΔkP_k = \lfloor 0.8 \times P_{k-1} \rfloor + \Delta_k

where x\lfloor x \rfloor represents the greatest integer less than or equal to xx.

At the end of Month 3 (k=3k = 3), membership tiers are assigned based on final points P3P_3:
- VIP Tier: P3150P_3 \ge 150
- Premium Tier: 80P3<15080 \le P_3 < 150
- Standard Tier: P3<80P_3 < 80

Match each initial customer profile (defined by initial points P0P_0 and monthly additions Δ1,Δ2,Δ3\Delta_1, \Delta_2, \Delta_3) to its corresponding final state at the end of Month 3.

  • Profile 1: P0=100P_0 = 100; additions Δ1=50,Δ2=10,Δ3=40\Delta_1 = 50, \Delta_2 = 10, \Delta_3 = 40Final Points: 131 (Premium Tier)
  • Profile 2: P0=150P_0 = 150; additions Δ1=30,Δ2=40,Δ3=50\Delta_1 = 30, \Delta_2 = 40, \Delta_3 = 50Final Points: 178 (VIP Tier)
  • Profile 3: P0=90P_0 = 90; additions Δ1=0,Δ2=10,Δ3=20\Delta_1 = 0, \Delta_2 = 10, \Delta_3 = 20Final Points: 73 (Standard Tier)
  • Profile 4: P0=200P_0 = 200; additions Δ1=0,Δ2=10,Δ3=30\Delta_1 = 0, \Delta_2 = 10, \Delta_3 = 30Final Points: 140 (Premium Tier)

Answer

Profile 1 matches Final Points: 131 (Premium Tier); Profile 2 matches Final Points: 178 (VIP Tier); Profile 3 matches Final Points: 73 (Standard Tier); Profile 4 matches Final Points: 140 (Premium Tier).
Each profile is evaluated by computing the exact state update Pk=0.8Pk1+ΔkP_k = \lfloor 0.8 \cdot P_{k-1} \rfloor + \Delta_k sequentially over three transitions. Profile 1 yields 131 points (Premium Tier), Profile 2 yields 178 points (VIP Tier), Profile 3 yields 73 points (Standard Tier), and Profile 4 yields 140 points (Premium Tier).

Step-by-Step Solution

1
Apply the state transition formula Pk=0.8×Pk1+ΔkP_k = \lfloor 0.8 \times P_{k-1} \rfloor + \Delta_k iteratively across months k=1,2,3k = 1, 2, 3 for Profile 1.
P1=80+50=130P_1 = 80 + 50 = 130; P2=104+10=114P_2 = 104 + 10 = 114; P3=91+40=131P_3 = 91 + 40 = 131. Tier: Premium.
Tracking sequential updates ensures each intermediate decay and point addition step is accounted for accurately.
2
Apply the state transition formula iteratively across months k=1,2,3k = 1, 2, 3 for Profile 2.
P1=120+30=150P_1 = 120 + 30 = 150; P2=120+40=160P_2 = 120 + 40 = 160; P3=128+50=178P_3 = 128 + 50 = 178. Tier: VIP.
Continuous accumulation and decay calculation determines the final state threshold reached.
3
Apply the state transition formula iteratively across months k=1,2,3k = 1, 2, 3 for Profile 3.
P1=72+0=72P_1 = 72 + 0 = 72; P2=57+10=67P_2 = 57 + 10 = 67; P3=53+20=73P_3 = 53 + 20 = 73. Tier: Standard.
Floor function truncation must be evaluated at each step prior to adding monthly points.
4
Apply the state transition formula iteratively across months k=1,2,3k = 1, 2, 3 for Profile 4.
P1=160+0=160P_1 = 160 + 0 = 160; P2=128+10=138P_2 = 128 + 10 = 138; P3=110+30=140P_3 = 110 + 30 = 140. Tier: Premium.
Evaluating high starting values shows how retention decay influences final tier classification.

Key Concept

Sequential state transitions with floor function decay and additive step updates
Rate this question