Question

Difficulty: Very hardAlgebraic Word Problems and Equation Modeling

Working together at their respective constant rates, Machine X and Machine Y can complete a specialized production order in 1212 hours. If Machine X works alone for 44 hours and Machine Y works alone for 99 hours, they complete 712\frac{7}{12} of the total order. Machine Z operates at a constant rate that is 50%50\% greater than the rate of Machine X. How many hours would it take Machine Y and Machine Z working together to complete the entire order?

  1. 1010Answer
  2. B
    1212
  3. C
    1515
  4. D
    2020
  5. E
    4040

Answer

1010 hours
The correct answer is 1010 hours. Solving the system of equations yields individual rates of 130\frac{1}{30} order/hour for Machine X and 120\frac{1}{20} order/hour for Machine Y. A 50%50\% rate increase gives Machine Z a rate of 120\frac{1}{20} order/hour. Adding the rates of Machine Y and Machine Z yields a combined rate of 110\frac{1}{10} order/hour, which requires 1010 hours to complete one job.

Step-by-Step Solution

1
Define variables and model the joint rate equation.
Let xx be the rate of Machine X (order/hour) and yy be the rate of Machine Y (order/hour). Their combined rate equation is x+y=112x + y = \frac{1}{12}.
Working together for 1212 hours completes 11 full order.
2
Set up the second equation based on the partial work completed.
4x+9y=7124x + 9y = \frac{7}{12}.
Machine X works for 44 hours and Machine Y works for 99 hours to complete 712\frac{7}{12} of the order.
3
Solve the system of linear equations for xx and yy.
Express 4x+9y4x + 9y as 4(x+y)+5y=7124(x + y) + 5y = \frac{7}{12}. Substituting x+y=112x + y = \frac{1}{12} gives 4(112)+5y=712    412+5y=712    5y=312=14    y=1204\left(\frac{1}{12}\right) + 5y = \frac{7}{12} \implies \frac{4}{12} + 5y = \frac{7}{12} \implies 5y = \frac{3}{12} = \frac{1}{4} \implies y = \frac{1}{20}. Subsequently, x=112120=5360=260=130x = \frac{1}{12} - \frac{1}{20} = \frac{5 - 3}{60} = \frac{2}{60} = \frac{1}{30}.
Determines the individual work rates of Machine X and Machine Y.
4
Calculate the work rate of Machine Z.
Rate of Machine Z = 1.5×x=1.5×130=32×130=1201.5 \times x = 1.5 \times \frac{1}{30} = \frac{3}{2} \times \frac{1}{30} = \frac{1}{20}.
Machine Z is 50%50\% faster than Machine X.
5
Calculate the combined rate and total time for Machine Y and Machine Z.
Combined rate = y+z=120+120=220=110y + z = \frac{1}{20} + \frac{1}{20} = \frac{2}{20} = \frac{1}{10}. Total time = 1110=10\frac{1}{\frac{1}{10}} = 10 hours.
The inverse of the combined rate gives the total time required to finish one job.

Key Concept

Work Rates and Simultaneous Linear Modeling
Estimated Time:2m 30s
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