Question

Difficulty: EasyDivisibility, Factors, and Multiples

What is the smallest positive integer greater than 100100 that is divisible by 99?

Answer: 108

Answer

The smallest positive integer greater than 100100 that is divisible by 99 is 108108.
An integer is divisible by 9 if it is an integer multiple of 9. Multiples of 9 around 100 are 9×11=999 \times 11 = 99 and 9×12=1089 \times 12 = 108. Since 99 is not greater than 100, the smallest integer meeting the condition is 108.

Step-by-Step Solution

1
Divide 100 by 9 to locate the adjacent multiples of 9.
100=9×11+1100 = 9 \times 11 + 1
This shows that 9×11=999 \times 11 = 99 is the largest multiple of 9 that is less than or equal to 100.
2
Determine the next multiple of 9 by adding 9 to 99 (or evaluating 9×129 \times 12).
99+9=10899 + 9 = 108
Since 99 is less than 100, the next consecutive multiple of 9 must be the smallest multiple strictly greater than 100.

Key Concept

Divisibility and Multiples of Integers
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