Question

Difficulty: HardRange and Standard Deviation

A dataset XX consists of five positive integers with a mean of 12, a median of 12, a unique mode of 12, and a range of 8. If σ2\sigma^2 represents the variance (the square of the standard deviation) of dataset XX, what is the maximum possible value of σ2\sigma^2?

  1. A
    6.46.4
  2. B
    7.27.2
  3. 7.67.6Answer
  4. D
    8.08.0
  5. E
    8.48.4

Answer

The maximum possible value of the variance σ2\sigma^2 is 7.67.6.
To maximize variance σ2=15(xi12)2\sigma^2 = \frac{1}{5}\sum (x_i - 12)^2, data points must be placed as far from the mean of 12 as possible. For five ordered positive integers abcdea \le b \le c \le d \le e, the mean of 12 gives a+b+c+d+e=60a+b+c+d+e=60, the median of 12 gives c=12c=12, and the range of 8 gives e=a+8e=a+8. Substituting yields 2a+b+d=402a+b+d=40. Since b12b \le 12 and da+8d \le a+8, b+da+20b+d \le a+20, leading to 3a203a \ge 20, so a7a \ge 7. Testing a=7a=7 gives e=15e=15 and b+d=26b+d=26. To keep 12 as the unique mode, b=12b=12 and d=14d=14, forming dataset {7,12,12,14,15}\{7, 12, 12, 14, 15\}. The squared deviations from 12 are (5)2+02+02+22+32=25+0+0+4+9=38(-5)^2 + 0^2 + 0^2 + 2^2 + 3^2 = 25 + 0 + 0 + 4 + 9 = 38. Dividing by 5 yields the maximum variance of 7.67.6.

Step-by-Step Solution

1
Express the five integers in ascending order and set up equations from given statistics.
Let the integers be abcdea \le b \le c \le d \le e. Mean = 12 implies a+b+c+d+e=60a + b + c + d + e = 60. Median = 12 implies c=12c = 12. Range = 8 implies e=a+8e = a + 8.
Translating statistical measures into algebraic constraints provides the boundary conditions for the dataset.
2
Substitute known values into the sum equation and determine constraints on aa.
a+b+12+d+(a+8)=60    2a+b+d=40a + b + 12 + d + (a + 8) = 60 \implies 2a + b + d = 40. Since b12b \le 12 and de=a+8d \le e = a + 8, we have b+da+20b + d \le a + 20. Thus 2a+(a+20)40    3a20    a72a + (a + 20) \ge 40 \implies 3a \ge 20 \implies a \ge 7.
Determining the minimum value of aa is critical because smaller values of aa allow larger deviations from the mean of 12.
3
Evaluate valid dataset configurations for a=7a = 7 that satisfy the unique mode condition.
If a=7a = 7, then e=15e = 15, and b+d=26b + d = 26. With b12b \le 12 and d15d \le 15, and requiring 12 to be the unique mode, the only valid integer set is {7,12,12,14,15}\{7, 12, 12, 14, 15\}.
The set must maintain 12 as the unique mode while maximizing the dispersion of values.
4
Calculate the variance σ2\sigma^2 for the set {7,12,12,14,15}\{7, 12, 12, 14, 15\}.
Deviations from 12 are 5,0,0,2,3-5, 0, 0, 2, 3. Squared deviations are 25,0,0,4,925, 0, 0, 4, 9. Sum of squared deviations = 38. Variance σ2=385=7.6\sigma^2 = \frac{38}{5} = 7.6.
Variance is defined as the mean of the squared deviations from the dataset mean.

Key Concept

Properties of Variance and Standard Deviation under Range and Central Tendency Constraints
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