A positive integer has exactly three distinct prime factors. If has exactly positive divisors, what is the minimum possible value of ?
Answer: 1080
Answer
The minimum possible value of is 1080.
By prime factorizing , the number of divisors of is given by . Decomposing 147 into three factors greater than 1 gives , which determines the exponents , , and . Minimizing by assigning the smallest primes (2, 3, and 5) to these exponents yields .
Step-by-Step Solution
Key Concept
Determining the prime factorization and number of divisors of prime power expressions