A biotechnology laboratory operates two automated synthesis workflows, System X and System Y, to manufacture two compounds, Alpha () and Beta (). System X operates for hours, producing at a rate of and at a rate of . System Y operates for hours, producing at a rate of and at a rate of . The combined mass of compounds and produced across both workflows is exactly . Furthermore, the system's operating efficiency requires that the ratio of operating hours equals the ratio of total mass produced . What is the total operating time, , in hours?
Answer: 20 hours
Answer
The total operating time of both workflows is 20 hours.
Representing the total production of compounds A and B as functions of hours x and y yields the linear total mass equation 8x + 23y = 340 and the ratio relation x/y = B/A, which simplifies to the homogeneous quadratic 3x^2 + 10xy - 8y^2 = 0. Factoring gives (3x - 2y)(x + 4y) = 0. Since operating hours are strictly positive, x = (2/3)y. Substituting this into the linear equation yields (85/3)y = 340, giving y = 12 hours and x = 8 hours. The total operating time is 8 + 12 = 20 hours.
Step-by-Step Solution
Key Concept
Solving non-linear systems of simultaneous equations involving ratio constraints and quadratic factorization
Estimated Time:2m 30s