Question

Difficulty: MediumDivisibility, Factors, and Multiples

Let nn be the smallest positive integer that is a multiple of 15 and leaves a remainder equivalent to 2-2 when divided by 7. What is the value of nn?

  1. A
    30
  2. 75Answer
  3. C
    45
  4. D
    105
  5. E
    60

Answer

75
The correct value is 75. Since nn is a multiple of 15, n=15kn = 15k. A remainder of 2-2 when divided by 7 means n5(mod7)n \equiv 5 \pmod 7. Substituting n=15kn = 15k gives 15k5(mod7)15k \equiv 5 \pmod 7, which simplifies to k5(mod7)k \equiv 5 \pmod 7 since 151(mod7)15 \equiv 1 \pmod 7. The smallest positive integer value for kk is 5, giving n=15×5=75n = 15 \times 5 = 75.

Step-by-Step Solution

1
Express nn as a multiple of 15
n=15kn = 15k for some positive integer kk
Since nn is a multiple of 15, it must be of the form 15k15k.
2
Convert the negative remainder condition into a standard positive remainder modulo 7
n25(mod7)n \equiv -2 \equiv 5 \pmod 7
A remainder of 2-2 modulo 7 is equivalent to 7+(2)=57 + (-2) = 5.
3
Solve the modular congruence for kk
k=5k = 5
Substituting n=15kn = 15k into 15k5(mod7)15k \equiv 5 \pmod 7 gives 1k5(mod7)1k \equiv 5 \pmod 7 because 151(mod7)15 \equiv 1 \pmod 7. The smallest positive integer solution is k=5k = 5.
4
Calculate the value of nn
n=15×5=75n = 15 \times 5 = 75
Multiplying 15 by k=5k = 5 yields 75.

Key Concept

Modular Arithmetic and Remainder Properties
Estimated Time:1m 30s
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