Question

Difficulty: MediumQuestion Stem Simplification and Target Rephrasing

For all positive real numbers aa and bb, the Data Sufficiency Yes/No target question "Is a2+3abb2+3ab>1\frac{a^2 + 3ab}{b^2 + 3ab} > 1?" is algebraically equivalent to asking "Is a>ba > b?"

Answer: Answer

Answer

True. The target question simplifies directly to "Is a>ba > b?"
The statement is true because cross-multiplying the strictly positive denominator b2+3abb^2 + 3ab and subtracting the shared term 3ab3ab reduces a2+3abb2+3ab>1\frac{a^2 + 3ab}{b^2 + 3ab} > 1 directly to a2>b2a^2 > b^2. Since aa and bb are both positive, a2>b2a^2 > b^2 is logically equivalent to a>ba > b.

Step-by-Step Solution

1
Determine the sign of the denominator.
Since a>0a > 0 and b>0b > 0, b2+3ab>0b^2 + 3ab > 0.
Knowing the denominator is strictly positive ensures we can cross-multiply without reversing the inequality sign.
2
Cross-multiply the inequality by the denominator.
a2+3ab>b2+3aba^2 + 3ab > b^2 + 3ab
Multiplying both sides of a2+3abb2+3ab>1\frac{a^2 + 3ab}{b^2 + 3ab} > 1 by (b2+3ab)(b^2 + 3ab) clears the fraction.
3
Subtract 3ab3ab from both sides.
a2>b2a^2 > b^2
Eliminating the common linear term isolates the quadratic terms.
4
Take the square root of both sides.
a>ba > b
Because aa and bb are positive, a2>b2a^2 > b^2 holds if and only if a>ba > b.

Key Concept

Data Sufficiency Question Stem Simplification
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