Question

Difficulty: MediumSystems of Linear Equations

A research laboratory placed two orders for high-precision sensors. The first order, consisting of 55 acoustic sensors and 33 thermal sensors, cost a total of $1160\$1{}160. The second order, consisting of 33 acoustic sensors and 55 thermal sensors, cost a total of $1080\$1{}080. If each acoustic sensor costs the same amount and each thermal sensor costs the same amount, what is the combined cost of 11 acoustic sensor and 11 thermal sensor?

  1. A
    $140\$140
  2. B
    $160\$160
  3. $280\$280Answer
  4. D
    $320\$320
  5. E
    $560\$560

Answer

The combined cost of 1 acoustic sensor and 1 thermal sensor is $280\$280.
By representing the acoustic sensor price as aa and thermal sensor price as tt, we form two equations: 5a+3t=11605a + 3t = 1160 and 3a+5t=10803a + 5t = 1080. Adding both equations gives 8a+8t=22408a + 8t = 2240. Dividing the entire equation by 88 isolates a+t=280a + t = 280.

Step-by-Step Solution

1
Define variables and write the system of equations based on the problem statement.
Let aa be the price of one acoustic sensor and tt be the price of one thermal sensor.
Equation 1: 5a+3t=11605a + 3t = 1160
Equation 2: 3a+5t=10803a + 5t = 1080
Translate word problem conditions into algebraic equations.
2
Add the two equations together to find a direct linear combination.
(5a+3t)+(3a+5t)=1160+1080    8a+8t=2240(5a + 3t) + (3a + 5t) = 1160 + 1080 \implies 8a + 8t = 2240
Since the target is a+ta + t, adding symmetric coefficients yields a common factor of 88, avoiding the need to solve for aa and tt individually.
3
Factor out 88 and solve for (a+t)(a + t).
8(a+t)=2240    a+t=22408=2808(a + t) = 2240 \implies a + t = \frac{2240}{8} = 280
Dividing the combined equation by 88 directly isolates the required quantity (a+t)(a + t).

Key Concept

Solving Linear Systems via Algebraic Combinations
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