Question

Difficulty: MediumGreatest Common Divisor (GCD) and Least Common Multiple (LCM)

For two positive integers aa and bb, the greatest common divisor is 1515 and the least common multiple is 180180. If a=45a = 45, what is the value of bb?

  1. A
    12
  2. B
    15
  3. 60Answer
  4. D
    135
  5. E
    180

Answer

60
For any two positive integers aa and bb, the product of their greatest common divisor and their least common multiple equals the product of the two numbers, expressed as GCD(a,b)×LCM(a,b)=a×b\text{GCD}(a, b) \times \text{LCM}(a, b) = a \times b. Plugging in the given values yields 15×180=45×b15 \times 180 = 45 \times b. Dividing 27002700 by 4545 results in 6060.

Step-by-Step Solution

1
Recall the fundamental relation between GCD and LCM for two positive integers.
GCD(a,b)×LCM(a,b)=a×b\text{GCD}(a, b) \times \text{LCM}(a, b) = a \times b
The product of the greatest common divisor and the least common multiple of two positive integers is equal to the product of the integers themselves.
2
Substitute the given values into the formula.
15×180=45×b15 \times 180 = 45 \times b
We are given GCD(a,b)=15\text{GCD}(a,b) = 15, LCM(a,b)=180\text{LCM}(a,b) = 180, and a=45a = 45.
3
Solve for bb.
b=15×18045=1803=60b = \frac{15 \times 180}{45} = \frac{180}{3} = 60
Dividing both sides by 4545 simplifies to 180÷3=60180 \div 3 = 60.

Key Concept

Relationship between GCD, LCM, and the product of two positive integers.
Estimated Time:1m 30s
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