Question

Difficulty: Very hardPositive and Negative Number Properties

If xx, yy, and zz are non-zero real numbers such that xyz2<0x y z^2 < 0, xy>0x - y > 0, and xz<yz\frac{x}{z} < \frac{y}{z}, which of the following MUST be true?

  1. xzy<0\frac{x - z}{y} < 0Answer
  2. B
    xyz>0\frac{x - y}{z} > 0
  3. C
    x^2 - y^2 > 0
  4. D
    yzx<0\frac{y - z}{x} < 0
  5. E
    x+zy>0\frac{x + z}{y} > 0

Answer

xzy<0\frac{x - z}{y} < 0
From z2>0z^2 > 0, the inequality xyz2<0x y z^2 < 0 implies xy<0x y < 0, so xx and yy have opposite signs. Since xy>0    x>yx - y > 0 \implies x > y, xx must be positive (x>0x > 0) and yy must be negative (y<0y < 0). Next, comparing x>yx > y with xz<yz\frac{x}{z} < \frac{y}{z} shows that dividing by zz reversed the inequality sign, which proves zz is negative (z<0z < 0). Evaluating xzy\frac{x - z}{y}: the numerator xzx - z is positive minus negative, which equals positive plus positive (strictly positive), while the denominator yy is strictly negative. A positive value divided by a negative value is always negative, so xzy<0\frac{x - z}{y} < 0 MUST be true.

Step-by-Step Solution

1
Determine the relative signs of xx and yy using xyz2<0x y z^2 < 0.
xx and yy must have opposite signs (xy<0x y < 0).
Since z0z \neq 0, z2>0z^2 > 0 is always positive. Dividing xyz2<0x y z^2 < 0 by z2z^2 yields xy<0x y < 0.
2
Determine the individual signs of xx and yy using xy>0x - y > 0.
x>0x > 0 (positive) and y<0y < 0 (negative).
xy>0    x>yx - y > 0 \implies x > y. Since xx and yy have opposite signs and xx is strictly greater than yy, xx must be positive and yy must be negative.
3
Determine the sign of zz using xz<yz\frac{x}{z} < \frac{y}{z}.
z<0z < 0 (negative).
We know x>yx > y. When dividing both sides of x>yx > y by zz, the inequality direction reverses to <<. An inequality sign flips if and only if the divisor zz is negative.
4
Evaluate the expression xzy\frac{x - z}{y}.
xzy<0\frac{x - z}{y} < 0
Because x>0x > 0 and z<0z < 0, z>0-z > 0, so the numerator xz=x+(z)x - z = x + (-z) is the sum of two positive numbers, which is positive. The denominator yy is negative. Dividing a positive number by a negative number yields a negative result.

Key Concept

Deducing variable signs from product conditions and inequality sign reversal rules
Estimated Time:2m 0s
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