Question

Difficulty: HardLinear Equations in One and Two Variables

A retail store sets the selling price, PP, of a custom item based on its wholesale cost, CC, according to the linear equation P=1.4C+20P = 1.4C + 20. The store's profit on each item is defined as PCP - C. If the profit on a certain item is also equal to 0.2P+400.2P + 40, what is the wholesale cost, CC, of the item in dollars?

Answer: 200 dollars

Answer

The wholesale cost CC of the item is $200.
By writing profit both as PC=0.4C+20P - C = 0.4C + 20 and as 0.2P+40=0.28C+440.2P + 40 = 0.28C + 44, we obtain a single linear equation in terms of CC: 0.4C+20=0.28C+440.4C + 20 = 0.28C + 44. Subtracting 0.28C0.28C and 2020 from both sides gives 0.12C=240.12C = 24, which simplifies to C=200C = 200.

Step-by-Step Solution

1
Substitute P=1.4C+20P = 1.4C + 20 into the standard profit expression PCP - C.
Profit = 0.4C+200.4C + 20
This expresses the profit solely as a linear function of the wholesale cost CC.
2
Substitute P=1.4C+20P = 1.4C + 20 into the alternative profit expression 0.2P+400.2P + 40.
Profit = 0.28C+440.28C + 44
This converts the given percentage-based profit condition into an expression dependent only on CC.
3
Set the two profit expressions equal to each other and solve the resulting single-variable linear equation.
0.12C=24    C=2000.12C = 24 \implies C = 200
Equating two valid expressions for the same quantity allows solving for the unknown variable CC.

Key Concept

Solving Systems of Linear Equations by Algebraic Substitution
Estimated Time:2m 0s
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