Question

Difficulty: MediumRemainders and Units Digit Cyclicity

An integer sequence is defined by Tn=7n(2)nT_n = 7^n - (-2)^n for all positive integers nn. What is the remainder when T40T_{40} is divided by 55?

  1. A
    1
  2. B
    2
  3. 0Answer
  4. D
    4
  5. E
    3

Answer

The remainder when T40T_{40} is divided by 55 is 00.
Modulo 55, 727 \equiv 2, so 7402407^{40} \equiv 2^{40}. Since 4040 is an even exponent, (2)40=240(-2)^{40} = 2^{40}. Substituting these into the formula yields T40240240=0(mod5)T_{40} \equiv 2^{40} - 2^{40} = 0 \pmod 5. Thus, the remainder is 00.

Step-by-Step Solution

1
Reduce the base 77 modulo 55
72(mod5)7 \equiv 2 \pmod 5, so 740240(mod5)7^{40} \equiv 2^{40} \pmod 5.
Simplifying the base makes modular exponentiation straightforward.
2
Evaluate the negative base term (2)40(-2)^{40}
Since 4040 is an even integer, (2)40=240(-2)^{40} = 2^{40}.
An even power of a negative number yields a positive result.
3
Compute T40T_{40} modulo 55
T40=740(2)40240240=0(mod5)T_{40} = 7^{40} - (-2)^{40} \equiv 2^{40} - 2^{40} = 0 \pmod 5.
Subtracting identical values yields 00.

Key Concept

Modular Arithmetic and Exponent Parity
Estimated Time:1m 30s
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