Question

Difficulty: EasyDivisibility, Factors, and Multiples

For any integer nn, which of the following expressions must be divisible by 22?

  1. n2+nn^2 + nAnswer
  2. B
    n2+1n^2 + 1
  3. C
    n3+1n^3 + 1
  4. D
    (n+1)2(n + 1)^2
  5. E
    2n+12n + 1

Answer

The expression n2+nn^2 + n is always divisible by 22 for any integer nn.
The expression n2+nn^2 + n factors into n(n+1)n(n + 1). Because nn and n+1n + 1 are consecutive integers, one of them must be even. Any integer multiplied by an even integer produces an even number, guaranteeing that n2+nn^2 + n is divisible by 22 for every integer nn.

Step-by-Step Solution

1
Factor the given algebraic expression.
n2+n=n(n+1)n^2 + n = n(n + 1)
Factoring out nn reveals the product of two consecutive integers.
2
Analyze the parity of consecutive integers nn and n+1n + 1.
In any pair of consecutive integers (n,n+1)(n, n + 1), exactly one number is even.
Even and odd integers alternate sequentially.
3
Determine divisibility by 22.
Because one of the factors is even (divisible by 22), their product n(n+1)n(n + 1) is always divisible by 22.
Any integer multiplied by an even number yields an even result.

Key Concept

The product of any two consecutive integers is always even and therefore divisible by 2.
Estimated Time:45s
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