Question

Difficulty: EasyQuadratic Equations and Polynomial Factoring

If 2x2+5x3=02x^2 + 5x - 3 = 0 and x>0x > 0, what is the value of xx?

Answer: 0.5

Answer

The value of xx is 0.5.
Factoring the quadratic equation 2x2+5x3=02x^2 + 5x - 3 = 0 yields (2x1)(x+3)=0(2x - 1)(x + 3) = 0. Setting each linear factor equal to zero gives two possible solutions for xx: x=0.5x = 0.5 and x=3x = -3. Because the problem stipulates that x>0x > 0, the negative solution is discarded, leaving x=0.5x = 0.5.

Step-by-Step Solution

1
Factor the quadratic expression
(2x1)(x+3)=0(2x - 1)(x + 3) = 0
Splitting the middle term 5x5x into 6xx6x - x allows grouping to factor by grouping.
2
Find the roots of the equation
x=0.5x = 0.5 or x=3x = -3
By the zero-product property, if the product of two factors is zero, at least one factor must be zero.
3
Apply the positivity constraint x>0x > 0
x=0.5x = 0.5
The root x=3x = -3 violates the given condition that xx must be strictly greater than zero.

Key Concept

Solving quadratic equations by factoring and applying domain constraints
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