Question

Difficulty: Very hardRatios, Rates, and Percentages

A commercial roastery blends two batches of coffee beans, Batch A and Batch R. Batch A contains whole beans and cracked beans in a mass ratio of 7:37:3. Batch R contains whole beans and cracked beans in a mass ratio of 3:23:2. A roaster combines xx kilograms of Batch A with yy kilograms of Batch R to create an unroasted blend in which the overall mass ratio of whole beans to cracked beans is 13:713:7.

During the roasting process, moisture evaporation causes whole beans to lose 10%10\% of their mass and cracked beans to lose 20%20\% of their mass. If the total mass of the roasted blend is 346346 kilograms, what was the initial mass xx of Batch A, in kilograms?

Answer: 200 kg

Answer

The initial mass of Batch A (xx) is 200 kg.
The correct calculation shows that equal masses of Batch A and Batch R (x=yx = y) satisfy the combined unroasted ratio of 13:713:7. Applying the respective 10%10\% and 20%20\% mass losses for whole and cracked beans results in a total roasted mass factor of 1.73x1.73x. Equating 1.73x=3461.73x = 346 gives x=200x = 200 kg.

Step-by-Step Solution

1
Set up expressions for initial whole and cracked bean masses
Batch A has 0.7x0.7x kg whole and 0.3x0.3x kg cracked beans; Batch R has 0.6y0.6y kg whole and 0.4y0.4y kg cracked beans.
Ratios 7:37:3 and 3:23:2 convert directly to component fractions 7/10=0.77/10 = 0.7, 3/10=0.33/10 = 0.3 for A, and 3/5=0.63/5 = 0.6, 2/5=0.42/5 = 0.4 for R.
2
Equate the total component ratio to 13:713:7 to find the relationship between xx and yy
x=yx = y
Setting 0.7x+0.6y0.3x+0.4y=137\frac{0.7x + 0.6y}{0.3x + 0.4y} = \frac{13}{7} and cross-multiplying yields 4.9x+4.2y=3.9x+5.2y4.9x + 4.2y = 3.9x + 5.2y, simplifying to x=yx = y.
3
Apply roasting mass loss percentages to compute total roasted mass in terms of xx
Total roasted mass = 1.73x1.73x
Whole beans retain 90%90\% mass (0.90×1.3x=1.17x0.90 \times 1.3x = 1.17x) and cracked beans retain 80%80\% mass (0.80×0.7x=0.56x0.80 \times 0.7x = 0.56x). Summing yields 1.17x+0.56x=1.73x1.17x + 0.56x = 1.73x.
4
Solve for xx given total roasted mass of 346346 kg
x=200x = 200
Dividing 346346 by 1.731.73 yields 200200 kg.

Key Concept

Weighted average ratios combined with proportional percentage change
Rate this question