Question

Difficulty: MediumOverlapping Sets and Venn Diagrams

A market research study examined the streaming service subscriptions of 250250 households. Every surveyed household subscribes to at least one of three streaming services: Service X, Service Y, or Service Z.

- 130130 households subscribe to Service X.
- 110110 households subscribe to Service Y.
- 120120 households subscribe to Service Z.
- 4040 households subscribe to both Service X and Service Y.
- 3535 households subscribe to both Service Y and Service Z.
- 4545 households subscribe to both Service X and Service Z.

How many households subscribe to all three streaming services?

Answer: 10 households

Answer

10 households subscribe to all three streaming services.
According to the Principle of Inclusion-Exclusion for three sets, XYZ=X+Y+Z(XY+YZ+XZ)+XYZ|X \cup Y \cup Z| = |X| + |Y| + |Z| - (|X \cap Y| + |Y \cap Z| + |X \cap Z|) + |X \cap Y \cap Z|. Since every household subscribes to at least one service, XYZ=250|X \cup Y \cup Z| = 250. Substituting the values yields 250=130+110+120(40+35+45)+XYZ250 = 130 + 110 + 120 - (40 + 35 + 45) + |X \cap Y \cap Z|, which simplifies to 250=240+XYZ250 = 240 + |X \cap Y \cap Z|. Solving for XYZ|X \cap Y \cap Z| gives 1010.

Step-by-Step Solution

1
Set up the Inclusion-Exclusion formula for three overlapping sets
Total = |X| + |Y| + |Z| - (|X ∩ Y| + |Y ∩ Z| + |X ∩ Z|) + |X ∩ Y ∩ Z|
Because every household subscribes to at least one service, the total number of households equals the union of all three sets.
2
Sum the individual set sizes and the pairwise intersection sizes
Sum of individual sets = 130 + 110 + 120 = 360; Sum of pairwise intersections = 40 + 35 + 45 = 120
Aggregating individual and overlapping counts simplifies substitution.
3
Substitute the values into the formula and solve for the intersection of all three sets
250 = 360 - 120 + |X ∩ Y ∩ Z| => 250 = 240 + |X ∩ Y ∩ Z| => |X ∩ Y ∩ Z| = 10
Subtracting 240 from 250 yields the exact count of households subscribing to all three services.

Key Concept

Inclusion-Exclusion Principle for Three Sets
Estimated Time:1m 30s
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