Question

Difficulty: MediumPercent Change and Interest

An initial investment of $8,000\$8,000 was deposited into an account earning an annual interest rate of r%r\%, compounded annually. If no additional deposits or withdrawals were made and the total balance in the account after 22 years was $11,520\$11,520, what is the value of rr?

Answer: 20

Answer

The value of rr is 20.
The compound interest formula for annual compounding is A=P(1+r100)tA = P\left(1 + \frac{r}{100}\right)^t. Substituting P=8,000P = 8,000, A=11,520A = 11,520, and t=2t = 2 gives 11,520=8,000(1+r100)211,520 = 8,000\left(1 + \frac{r}{100}\right)^2. Dividing both sides by 8,0008,000 yields (1+r100)2=1.44\left(1 + \frac{r}{100}\right)^2 = 1.44. Taking the square root gives 1+r100=1.21 + \frac{r}{100} = 1.2, so r100=0.20\frac{r}{100} = 0.20, which corresponds to r=20r = 20.

Step-by-Step Solution

1
Set up the compound interest equation using given principal and accumulated balance.
11,520 = 8,000 \left(1 + \frac{r}{100}\right)^2
Interest compounded annually over 22 years scales the initial principal by a factor of (1+r100)2\left(1 + \frac{r}{100}\right)^2.
2
Divide both sides by 8,0008,000 to isolate the annual growth factor squared.
\left(1 + \frac{r}{100}\right)^2 = \frac{11,520}{8,000} = 1.44
Finding the ratio of final balance to initial principal gives the overall multiplier over the two-year period.
3
Take the square root of both sides to obtain the single-year multiplier.
1 + \frac{r}{100} = \sqrt{1.44} = 1.2
Since the interest rate r>0r > 0, taking the positive square root gives the multiplier for one year.
4
Solve for rr.
r = (1.2 - 1) \times 100 = 20
Subtracting 11 yields the annual decimal interest rate of 0.200.20, which corresponds to 20%20\%.

Key Concept

Annual Compound Interest Rate Calculation
Rate this question