Question

Difficulty: HardQuadratic Equations and Polynomial Factoring

If x(x27x+12)=2(x27x+12)x(x^2 - 7x + 12) = 2(x^2 - 7x + 12), what is the sum of all distinct real values of xx that satisfy the equation?

  1. A
    2
  2. B
    5
  3. C
    7
  4. 9Answer
  5. E
    14

Answer

9
To find all solutions to x(x27x+12)=2(x27x+12)x(x^2 - 7x + 12) = 2(x^2 - 7x + 12), subtract the right side from the left to obtain (x2)(x27x+12)=0(x - 2)(x^2 - 7x + 12) = 0. Factoring the quadratic expression gives (x2)(x3)(x4)=0(x - 2)(x - 3)(x - 4) = 0. Setting each factor to zero reveals three distinct real roots: 2, 3, and 4. The sum of these roots is 2+3+4=92 + 3 + 4 = 9.

Step-by-Step Solution

1
Rearrange the equation to set one side to zero
x(x27x+12)2(x27x+12)=0x(x^2 - 7x + 12) - 2(x^2 - 7x + 12) = 0
Setting the equation to zero allows the application of the zero-product property without illegally dividing by variable expressions.
2
Factor out the common quadratic expression (x27x+12)(x^2 - 7x + 12)
(x2)(x27x+12)=0(x - 2)(x^2 - 7x + 12) = 0
Both terms share the common factor (x27x+12)(x^2 - 7x + 12).
3
Factor the quadratic component (x27x+12)(x^2 - 7x + 12) into linear factors
(x2)(x3)(x4)=0(x - 2)(x - 3)(x - 4) = 0
The quadratic factors into (x3)(x4)(x - 3)(x - 4) because (3)×(4)=12(-3) \times (-4) = 12 and (3)+(4)=7(-3) + (-4) = -7.
4
Apply the zero-product property to find all distinct real roots and compute their sum
Roots are x=2x = 2, x=3x = 3, and x=4x = 4. Sum = 2+3+4=92 + 3 + 4 = 9.
Setting each linear factor to zero gives the solutions. Summing these solutions yields 9.

Key Concept

Polynomial Factoring and the Zero-Product Property
Estimated Time:2m 0s
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