Question

Difficulty: MediumPrime Numbers and Prime Factorization

Let N=504N = 504. If MM is the smallest positive integer such that N×MN \times M is a perfect cube, what is the value of MM?

Answer: 147

Answer

The smallest positive integer MM such that 504×M504 \times M is a perfect cube is 147.
For an integer to be a perfect cube, the exponent of each prime factor in its prime factorization must be a multiple of 3. Prime factorizing 504 yields 23×32×712^3 \times 3^2 \times 7^1. The exponent of 2 is 3 (already a multiple of 3). The exponent of 3 is 2, which requires 1 additional factor of 3 to reach 3. The exponent of 7 is 1, which requires 2 additional factors of 7 (727^2) to reach 3. Therefore, the minimum value for MM is 31×72=3×49=1473^1 \times 7^2 = 3 \times 49 = 147.

Step-by-Step Solution

1
Express 504 as a product of its prime factors.
504=23×32×71504 = 2^3 \times 3^2 \times 7^1
Decomposing NN into prime factors allows analysis of the exponents required for perfect power conditions.
2
Apply the prime exponent rule for perfect cubes.
Every prime factor in N×MN \times M must have an exponent that is a multiple of 3.
A number KK is a perfect cube if and only if K=p13a×p23b×K = p_1^{3a} \times p_2^{3b} \times \dots
3
Calculate the missing prime factors needed to complete the cube.
M=332×731=31×72M = 3^{3-2} \times 7^{3-1} = 3^1 \times 7^2
To minimize MM, we raise each prime to the smallest non-negative power that rounds the existing exponent up to the nearest multiple of 3.
4
Evaluate the value of MM.
M=3×49=147M = 3 \times 49 = 147
Direct arithmetic computation.

Key Concept

Prime Factorization and Exponent Requirements for Perfect Powers
Estimated Time:1m 30s
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