Algebraic Equations and Systems in Data Sufficiency

42 questions

Question 1Question

If xx and yy are real numbers such that x3yx \neq 3y, what is the value of x+3yx + 3y?

(1) x2+6xy+9y2=49x^2 + 6xy + 9y^2 = 49
(2) x29y2=12(x3y)x^2 - 9y^2 = 12(x - 3y)

Show answer & explanation

Answer: Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

Answer

Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
Statement (1) simplifies to (x+3y)2=49(x + 3y)^2 = 49, which means x+3yx + 3y could be 77 or 7-7, so it is not sufficient. Statement (2) factors as (x3y)(x+3y)=12(x3y)(x - 3y)(x + 3y) = 12(x - 3y). Given x3yx \neq 3y, dividing both sides by (x3y)(x - 3y) uniquely determines x+3y=12x + 3y = 12. Thus, Statement (2) alone is sufficient while Statement (1) alone is not.

Step-by-Step Solution

1
Analyze Statement (1) algebraically
The expression x2+6xy+9y2x^2 + 6xy + 9y^2 is a perfect square trinomial equal to (x+3y)2(x + 3y)^2. Therefore, (x+3y)2=49(x + 3y)^2 = 49, which gives x+3y=7x + 3y = 7 or x+3y=7x + 3y = -7.
Because there are two distinct valid values for x+3yx + 3y, Statement (1) alone does not provide a unique value.
2
Analyze Statement (2) algebraically
The left side x29y2x^2 - 9y^2 factors as (x3y)(x+3y)(x - 3y)(x + 3y). The equation becomes (x3y)(x+3y)=12(x3y)(x - 3y)(x + 3y) = 12(x - 3y).
Since the stem specifies x3yx \neq 3y, we know x3y0x - 3y \neq 0, allowing us to divide both sides by (x3y)(x - 3y) without dividing by zero.
3
Solve the simplified equation from Statement (2)
Dividing gives x+3y=12x + 3y = 12.
This yields a single, unique value for the target expression x+3yx + 3y, making Statement (2) alone sufficient.

Key Concept

Algebraic Stem Rephrasing and Quadratic Degree Evaluation in Data Sufficiency
Estimated Time:1m 30s
Question 2Question

If xx and yy are real numbers, what is the value of xy\frac{x}{y}?

(1) x2yxy2=12x^2 y - x y^2 = 12
(2) xy=3x - y = 3

Show answer & explanation

Answer: Statements (1) and (2) TOGETHER are NOT sufficient.

Answer

Statements (1) and (2) TOGETHER are NOT sufficient.
Combining Statement (1) and Statement (2) allows substituting xy=3x - y = 3 into xy(xy)=12xy(x - y) = 12, yielding xy=4xy = 4. Solving the system xy=3x - y = 3 and xy=4xy = 4 gives two valid real solution pairs: (4,1)(4, 1) and (1,4)(-1, -4). The quotient xy\frac{x}{y} evaluates to 44 in the first case and 14\frac{1}{4} in the second case. Because a unique numerical value for xy\frac{x}{y} cannot be determined, the statements together are not sufficient.

Step-by-Step Solution

1
Evaluate Statement (1) independently.
Factor Statement (1): xy(xy)=12xy(x - y) = 12. Many pairs of real numbers (x,y)(x, y) satisfy this, such as (4,1)(4, 1) which gives xy=4\frac{x}{y} = 4, or (3,1)(3, 1) which gives 3(1)(2)=6123(1)(2) = 6 \neq 12. For (4,1)(4, 1), xy=4\frac{x}{y} = 4. For (x,y)=(2,1)(x, y) = (2, -1), 2(1)(3)=6122(-1)(3) = -6 \neq 12. However, choosing x=3+172x = \frac{3 + \sqrt{17}}{2} and y=3+172y = \frac{-3 + \sqrt{17}}{2} gives a different ratio. Since xy\frac{x}{y} can take infinitely many values, Statement (1) is not sufficient.
A single equation with two variables generally allows infinitely many solutions.
2
Evaluate Statement (2) independently.
Statement (2) gives xy=3x - y = 3. If x=4x = 4 and y=1y = 1, then xy=4\frac{x}{y} = 4. If x=5x = 5 and y=2y = 2, then xy=2.5\frac{x}{y} = 2.5. Since multiple values for xy\frac{x}{y} exist, Statement (2) is not sufficient.
A linear difference condition alone does not fix the ratio of two unknown quantities.
3
Evaluate Statements (1) and (2) combined.
Substitute xy=3x - y = 3 into xy(xy)=12xy(x - y) = 12 to get 3xy=12    xy=43xy = 12 \implies xy = 4. Express yy as x3x - 3 and substitute into xy=4xy = 4: x(x3)=4    x23x4=0    (x4)(x+1)=0x(x - 3) = 4 \implies x^2 - 3x - 4 = 0 \implies (x - 4)(x + 1) = 0. This yields two real solutions for xx: x=4x = 4 or x=1x = -1. If x=4x = 4, then y=1y = 1 and xy=41=4\frac{x}{y} = \frac{4}{1} = 4. If x=1x = -1, then y=4y = -4 and xy=14=14\frac{x}{y} = \frac{-1}{-4} = \frac{1}{4}.
Because two distinct values for xy\frac{x}{y} (44 and 14\frac{1}{4}) are possible, combined sufficiency fails.

Key Concept

Degree of non-linear algebraic systems and non-unique solutions in Data Sufficiency
Estimated Time:2m 0s
Question 3Question

If xx and yy are real numbers, what is the value of x+yx + y?

(1) 3x+3y=123x + 3y = 12
(2) xy=2x - y = 2

Show answer & explanation

Answer: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Answer

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
The correct option correctly identifies that Statement (1) alone is sufficient because dividing 3x+3y=123x + 3y = 12 by 3 yields x+y=4x + y = 4, directly answering the question without needing to solve for xx and yy individually. Statement (2) alone leaves x+yx + y undetermined.

Step-by-Step Solution

1
Analyze the target expression in the question stem.
The target to find is a single value for x+yx + y.
Rephrasing the question stem clarifies what exact numerical value or algebraic combination is required.
2
Evaluate Statement (1) independently: 3x+3y=123x + 3y = 12.
Factor out 3 to get 3(x+y)=123(x + y) = 12, then divide by 3 to obtain x+y=4x + y = 4.
Statement (1) gives a unique value for the target expression x+yx + y, so Statement (1) alone is sufficient.
3
Evaluate Statement (2) independently: xy=2x - y = 2.
If x=3x = 3 and y=1y = 1, then xy=2x - y = 2 and x+y=4x + y = 4. If x=4x = 4 and y=2y = 2, then xy=2x - y = 2 and x+y=6x + y = 6.
Multiple values for x+yx + y are possible, so Statement (2) alone is not sufficient.

Key Concept

Question Stem Rephrasing and Linear Expression Combination
Estimated Time:1m 0s
Question 4Question

If xx and yy are real numbers, what is the value of x3y3x^3 - y^3?

(1) xy=2x - y = 2
(2) x2+y2=10x^2 + y^2 = 10

Show answer & explanation

Answer: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Answer

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
Combining Statement (1) and Statement (2) allows us to determine the exact value of xy=3xy = 3. Substituting xy=2x - y = 2, x2+y2=10x^2 + y^2 = 10, and xy=3xy = 3 into the factored form x3y3=(xy)(x2+xy+y2)x^3 - y^3 = (x - y)(x^2 + xy + y^2) yields 2×(10+3)=262 \times (10 + 3) = 26. Because this value is uniquely determined, both statements together are sufficient while neither statement alone is sufficient.

Step-by-Step Solution

1
Rephrase the target expression using algebraic identities.
The target expression x3y3x^3 - y^3 factors into (xy)(x2+xy+y2)(x - y)(x^2 + xy + y^2).
To find x3y3x^3 - y^3, we need the values of (xy)(x - y) and (x2+xy+y2)(x^2 + xy + y^2), or equivalently, (xy)(x - y), (x2+y2)(x^2 + y^2), and xyxy.
2
Evaluate Statement (1) alone.
Statement (1) gives xy=2x - y = 2.
Without knowing x2+y2x^2 + y^2 or xyxy, x3y3x^3 - y^3 can take infinitely many values (for example, if x=2,y=0x=2, y=0, x3y3=8x^3-y^3=8; if x=3,y=1x=3, y=1, x3y3=26x^3-y^3=26). Thus, Statement (1) alone is NOT sufficient.
3
Evaluate Statement (2) alone.
Statement (2) gives x2+y2=10x^2 + y^2 = 10.
Without knowing xyx - y or xyxy, x3y3x^3 - y^3 can take multiple values (for example, if x=10,y=0x=\sqrt{10}, y=0, x3y3=1010x^3-y^3=10\sqrt{10}; if x=3,y=1x=3, y=1, x3y3=26x^3-y^3=26). Thus, Statement (2) alone is NOT sufficient.
4
Combine Statement (1) and Statement (2).
Square Statement (1): (xy)2=22    x22xy+y2=4(x - y)^2 = 2^2 \implies x^2 - 2xy + y^2 = 4. Substitute x2+y2=10x^2 + y^2 = 10: 102xy=4    2xy=6    xy=310 - 2xy = 4 \implies 2xy = 6 \implies xy = 3.
By squaring xyx - y and using x2+y2x^2 + y^2, we isolate a unique value for the product term xyxy.
5
Substitute known values into the target expression.
x3y3=(xy)(x2+y2+xy)=2×(10+3)=26x^3 - y^3 = (x - y)(x^2 + y^2 + xy) = 2 \times (10 + 3) = 26.
Since the expression evaluates to a single, unique numerical value (2626), the two statements together are sufficient.

Key Concept

Algebraic Expression Rephrasing and Solution Set Invariance in Data Sufficiency
Estimated Time:2m 0s
Question 5Question

If aa and bb are real numbers, what is the value of a2b2a^2 - b^2?

(1) a+b=7a + b = 7
(2) ab=3a - b = 3

Show answer & explanation

Answer: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Answer

Both statements together are sufficient, but neither statement alone is sufficient.
Factoring the target expression yields a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b). Neither statement alone gives both factors, so neither statement alone is sufficient. Combining Statement (1), which gives a+b=7a + b = 7, and Statement (2), which gives ab=3a - b = 3, allows us to calculate a2b2=7×3=21a^2 - b^2 = 7 \times 3 = 21. Therefore, both statements together are sufficient.

Step-by-Step Solution

1
Rephrase the target question stem algebraically.
Recognize that a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b). The objective is to find the value of the product (a+b)(ab)(a + b)(a - b).
Simplifying the target expression reduces the problem to finding the sum and difference of the variables.
2
Evaluate Statement (1) independently.
Statement (1) states a+b=7a + b = 7. Knowing only a+ba + b leaves aba - b unknown, so a2b2=7(ab)a^2 - b^2 = 7(a - b) can take infinitely many values. Statement (1) is insufficient.
A single linear equation with two variables cannot determine the value of a two-factor product unless the second factor is fixed.
3
Evaluate Statement (2) independently.
Statement (2) states ab=3a - b = 3. Knowing only aba - b leaves a+ba + b unknown, so a2b2=3(a+b)a^2 - b^2 = 3(a + b) can take infinitely many values. Statement (2) is insufficient.
A single difference equation does not uniquely determine the sum of two variables.
4
Evaluate Statements (1) and (2) together.
Combining both statements gives a+b=7a + b = 7 and ab=3a - b = 3. Substituting these values into the rephrased target expression yields a2b2=(7)(3)=21a^2 - b^2 = (7)(3) = 21. A unique numerical value is obtained. Statements combined are sufficient.
Having both component factors allows direct computation of their product without needing to solve for individual values of aa and bb first.

Key Concept

Algebraic Rephrasing and Difference of Squares in Data Sufficiency
Estimated Time:1m 0s
Question 6Question

What is the value of the real number kk?

(1) 4k8=124k - 8 = 12
(2) k2=25k^2 = 25

Show answer & explanation

Answer: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Answer

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Solving Statement (1) gives 4k=204k = 20, which simplifies to k=5k = 5. Because this is a single, unique value, Statement (1) alone is sufficient. Statement (2) gives k2=25k^2 = 25, which has two valid solutions (k=5k = 5 or k=5k = -5). Without additional constraints, Statement (2) alone is not sufficient to determine a single value for kk. Therefore, Statement (1) alone is sufficient, but Statement (2) alone is not sufficient.

Step-by-Step Solution

1
Evaluate Statement (1) independently
4k8=12    4k=20    k=54k - 8 = 12 \implies 4k = 20 \implies k = 5
Solving the linear equation gives a single, unique value for kk. Thus, Statement (1) alone is sufficient.
2
Evaluate Statement (2) independently
k2=25    k=5k^2 = 25 \implies k = 5 or k=5k = -5
Taking the square root yields two distinct possible values for kk. Because kk cannot be uniquely determined, Statement (2) alone is not sufficient.
3
Select the Data Sufficiency decision key
Statement (1) is sufficient, but Statement (2) is not.
This corresponds to the standard option where Statement (1) alone is sufficient.

Key Concept

Linear vs. Quadratic Degree Sufficiency in Data Sufficiency
Question 7Question

If xx is a real number, what is the value of (x+3)2(x + 3)^2?

(1) x2+6x=7x^2 + 6x = 7
(2) x=1x = 1

Show answer & explanation

Answer: EACH statement ALONE is sufficient.

Answer

Each statement alone is sufficient.
Expanding the target expression (x+3)2(x + 3)^2 gives x2+6x+9x^2 + 6x + 9. Statement (1) provides x2+6x=7x^2 + 6x = 7, which can be directly substituted into the expanded expression to get 7+9=167 + 9 = 16, yielding a unique value. Statement (2) explicitly provides x=1x = 1, which gives (1+3)2=16(1 + 3)^2 = 16. Because each statement independently provides enough information to determine a single value for the expression, the option stating that each statement alone is sufficient is correct.

Step-by-Step Solution

1
Rephrase the target expression using algebraic expansion.
(x+3)2=x2+6x+9(x + 3)^2 = x^2 + 6x + 9
Expanding the binomial allows direct comparison with given algebraic statements.
2
Evaluate Statement (1) using the expanded target expression.
Since x2+6x=7x^2 + 6x = 7, substituting this into x2+6x+9x^2 + 6x + 9 gives 7+9=167 + 9 = 16. Alternatively, solving x2+6x7=0x^2 + 6x - 7 = 0 yields x=1x = 1 or x=7x = -7. If x=1x = 1, (1+3)2=16(1 + 3)^2 = 16. If x=7x = -7, (7+3)2=(4)2=16(-7 + 3)^2 = (-4)^2 = 16. Both roots yield the exact same value of 1616.
Statement (1) alone uniquely determines the target value.
3
Evaluate Statement (2) independently.
Given x=1x = 1, substituting directly into the target expression gives (1+3)2=42=16(1 + 3)^2 = 4^2 = 16.
Statement (2) alone uniquely determines the target value.
4
Conclude sufficiency based on independent evaluations.
Both Statement (1) alone and Statement (2) alone are sufficient.
Since each statement independently determines a single value of 16, EACH statement ALONE is sufficient.

Key Concept

Algebraic Expression Expansion and Target Rephrasing in Data Sufficiency
Estimated Time:1m 0s
Question 8Question

If pp and qq are numbers, what is the value of the product pqpq?

(1) (p+q)2=49(p + q)^2 = 49
(2) p2+q2=25p^2 + q^2 = 25

Show answer & explanation

Answer: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Answer

Both statements together are sufficient to determine that pq=12pq = 12, but neither statement alone is sufficient.
The correct option states that both statements together are sufficient, but neither alone is sufficient. Expanding (p+q)2=p2+2pq+q2(p+q)^2 = p^2 + 2pq + q^2 allows substituting (p+q)2=49(p+q)^2 = 49 from statement (1) and p2+q2=25p^2 + q^2 = 25 from statement (2), yielding 49=25+2pq49 = 25 + 2pq, which uniquely determines pq=12pq = 12. Neither statement alone isolates pqpq.

Step-by-Step Solution

1
Rephrase the target question using algebraic identities
Recall the identity (p+q)2=p2+2pq+q2(p + q)^2 = p^2 + 2pq + q^2. Rearranging gives 2pq=(p+q)2(p2+q2)2pq = (p + q)^2 - (p^2 + q^2). Thus, knowing both (p+q)2(p + q)^2 and (p2+q2)(p^2 + q^2) will determine pqpq.
Target rephrasing simplifies evaluating statement sufficiency.
2
Evaluate Statement (1) independently
Statement (1) gives (p+q)2=49(p + q)^2 = 49. If p=7p = 7 and q=0q = 0, then pq=0pq = 0. If p=4p = 4 and q=3q = 3, then (4+3)2=49(4+3)^2 = 49 and pq=12pq = 12. Multiple values for pqpq exist.
A statement is sufficient only if it yields one unique value for the target expression.
3
Evaluate Statement (2) independently
Statement (2) gives p2+q2=25p^2 + q^2 = 25. If p=5p = 5 and q=0q = 0, then pq=0pq = 0. If p=4p = 4 and q=3q = 3, then 42+32=254^2 + 3^2 = 25 and pq=12pq = 12. Multiple values for pqpq exist.
Statement (2) alone does not yield a unique product.
4
Combine Statement (1) and Statement (2)
Substitute (p+q)2=49(p + q)^2 = 49 and p2+q2=25p^2 + q^2 = 25 into (p+q)2=p2+2pq+q2(p + q)^2 = p^2 + 2pq + q^2 to get 49=25+2pq2pq=24pq=1249 = 25 + 2pq 2pq = 24 pq = 12. A single, unique value is found.
Combining the statements provides enough information to determine the value of the target expression pqpq uniquely.

Key Concept

Algebraic Expression Manipulation via Quadratic Identities
Question 9Question

If aa and bb are non-zero real numbers, what is the value of ab\frac{a}{b}?

(1) 5a3b=05a - 3b = 0
(2) a+b=8a + b = 8

Show answer & explanation

Answer: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Answer

Statement (1) ALONE is sufficient to determine the value of ab\frac{a}{b}, but statement (2) alone is not sufficient.
Statement (1) can be rearranged algebraically to 5a=3b5a = 3b, which directly gives ab=35\frac{a}{b} = \frac{3}{5}, providing a single definitive value. Statement (2), a+b=8a + b = 8, allows infinitely many pairs of (a,b)(a, b) yielding different ratios for ab\frac{a}{b}. Therefore, Statement (1) alone is sufficient, while Statement (2) alone is not.

Step-by-Step Solution

1
Rephrase the question stem target
The target is to find a numerical value for the ratio ab\frac{a}{b}.
Simplifying the target helps determine if an equation directly yields the ratio without needing individual variable values.
2
Evaluate Statement (1) independently: 5a3b=05a - 3b = 0
Rearranging gives 5a=3b5a = 3b. Dividing both sides by 5b5b (since b0b \neq 0) yields ab=35\frac{a}{b} = \frac{3}{5}.
This yields a single, unique numerical value for the target expression. Thus, Statement (1) alone is sufficient.
3
Evaluate Statement (2) independently: a+b=8a + b = 8
If a=4a = 4 and b=4b = 4, then ab=1\frac{a}{b} = 1. If a=2a = 2 and b=6b = 6, then ab=13\frac{a}{b} = \frac{1}{3}.
Multiple values of the ratio ab\frac{a}{b} are possible. Thus, Statement (2) alone is not sufficient.

Key Concept

Determining ratios from homogeneous linear equations in Data Sufficiency
Question 10Question

If mm and nn are non-zero real numbers, what is the value of m2+n2mn\frac{m^2 + n^2}{mn}?

(1) m2n+mn2=6(m+n)m^2 n + m n^2 = 6(m + n)
(2) m2n2=3(mn)m^2 - n^2 = 3(m - n)

Show answer & explanation

Answer: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Answer

Both statements together are sufficient, but neither statement alone is sufficient.
Evaluating each statement alone yields multiple possible numerical outcomes because factoring produces independent cases (m+n=0m+n=0 vs mn=6mn=6 for the first statement, and mn=0m-n=0 vs m+n=3m+n=3 for the second). However, when combining both statements, three of the four sub-cases fail: two violate non-zero or consistency conditions, and the sub-case where mn=6mn=6 and m+n=3m+n=3 has a negative discriminant (324(1)(6)=15<03^2 - 4(1)(6) = -15 < 0), yielding no real solutions. This leaves only the sub-case mn=6mn=6 and mn=0m-n=0, which uniquely determines the value of the target expression to be 2. Therefore, both statements together are sufficient.

Step-by-Step Solution

1
Rephrase the target expression.
The target expression m2+n2mn\frac{m^2 + n^2}{mn} can be rewritten as mn+nm\frac{m}{n} + \frac{n}{m}. We need a unique numerical value for this expression.
Simplifying the target helps evaluate what parameters or relationships are required.
2
Evaluate Statement (1) independently.
Rearrange Statement (1): mn(m+n)6(m+n)=0    (mn6)(m+n)=0mn(m + n) - 6(m + n) = 0 \implies (mn - 6)(m + n) = 0. This gives two cases: Case 1: m+n=0    n=mm + n = 0 \implies n = -m. Since m,n0m, n \neq 0, m2+(m)2m(m)=2m2m2=2\frac{m^2 + (-m)^2}{m(-m)} = \frac{2m^2}{-m^2} = -2. Case 2: mn=6mn = 6. For instance, if m=2,n=3m = 2, n = 3, then 4+96=136\frac{4+9}{6} = \frac{13}{6}. Multiple values exist (2-2 and 136\frac{13}{6}), so Statement (1) alone is NOT sufficient.
Factoring instead of dividing by (m+n)(m+n) preserves the root m+n=0m+n=0.
3
Evaluate Statement (2) independently.
Rearrange Statement (2): (mn)(m+n)3(mn)=0    (mn)(m+n3)=0(m - n)(m + n) - 3(m - n) = 0 \implies (m - n)(m + n - 3) = 0. This gives two cases: Case 1: mn=0    m=nm - n = 0 \implies m = n. Since m,n0m, n \neq 0, m2+m2m2=2\frac{m^2 + m^2}{m^2} = 2. Case 2: m+n=3m + n = 3. For instance, if m=1,n=2m = 1, n = 2, then 1+42=52\frac{1+4}{2} = \frac{5}{2}. Multiple values exist (22 and 52\frac{5}{2}), so Statement (2) alone is NOT sufficient.
Factoring preserves the root mn=0m-n=0.
4
Combine Statement (1) and Statement (2).
We test the four combinations of cases:
- Case A (m+n=0m + n = 0) & Case X (mn=0m - n = 0): System gives m=0,n=0m = 0, n = 0. Contradicts the condition that m,nm, n are non-zero.
- Case A (m+n=0m + n = 0) & Case Y (m+n=3m + n = 3): 0=30 = 3, impossible.
- Case B (mn=6mn = 6) & Case X (mn=0m - n = 0): m=n    m2=6    m=n=±6m = n \implies m^2 = 6 \implies m = n = \pm\sqrt{6}. Here m2+n2mn=6+66=2\frac{m^2+n^2}{mn} = \frac{6+6}{6} = 2.
- Case B (mn=6mn = 6) & Case Y (m+n=3m + n = 3): n=3m    m(3m)=6    m23m+6=0n = 3 - m \implies m(3-m) = 6 \implies m^2 - 3m + 6 = 0. The discriminant is b24ac=924=15<0b^2 - 4ac = 9 - 24 = -15 < 0, which yields no real solutions for mm and nn.

Only Case B & Case X yields valid real non-zero solutions, providing a unique value of 2.
Checking real constraints eliminates non-real systems and isolates a single valid numerical outcome.

Key Concept

Factoring non-linear algebraic systems without illegal variable division, and verifying real-number constraints using discriminants in Data Sufficiency.
Estimated Time:2m 30s
Question 11Question

If xx and yy are real numbers such that x+y0x + y \neq 0, what is the value of x3+y3x+y\frac{x^3 + y^3}{x + y}?

(1) x2xy+y2=12x^2 - xy + y^2 = 12
(2) x2+y2=20x^2 + y^2 = 20 and xy=8xy = 8

Show answer & explanation

Answer: EACH statement ALONE is sufficient.

Answer

EACH statement ALONE is sufficient.
Factoring the numerator using the sum of cubes identity x3+y3=(x+y)(x2xy+y2)x^3 + y^3 = (x + y)(x^2 - xy + y^2) allows canceling (x+y)(x + y), since x+y0x + y \neq 0. Thus, the question asks for the value of x2xy+y2x^2 - xy + y^2. Statement (1) directly states that x2xy+y2=12x^2 - xy + y^2 = 12, which is sufficient. Statement (2) gives x2+y2=20x^2 + y^2 = 20 and xy=8xy = 8, so x2xy+y2=(x2+y2)xy=208=12x^2 - xy + y^2 = (x^2 + y^2) - xy = 20 - 8 = 12, which is also sufficient. Since each statement independently yields a unique value, the correct choice states that each statement alone is sufficient.

Step-by-Step Solution

1
Simplify and rephrase the target expression in the question stem.
Since x+y0x + y \neq 0, factor the numerator using the sum of cubes formula x3+y3=(x+y)(x2xy+y2)x^3 + y^3 = (x + y)(x^2 - xy + y^2). The expression simplifies to (x+y)(x2xy+y2)x+y=x2xy+y2\frac{(x + y)(x^2 - xy + y^2)}{x + y} = x^2 - xy + y^2. The question target is equivalent to finding the value of x2xy+y2x^2 - xy + y^2.
Simplifying the target expression before analyzing the statements eliminates unnecessary variables and reveals the exact algebraic value needed.
2
Evaluate Statement (1) independently.
Statement (1) gives x2xy+y2=12x^2 - xy + y^2 = 12. Since this matches the simplified question target directly, the value is uniquely determined as 12.
Statement (1) provides the exact value of the rephrased target expression.
3
Evaluate Statement (2) independently.
Statement (2) provides x2+y2=20x^2 + y^2 = 20 and xy=8xy = 8. Substituting these into the target expression x2xy+y2=(x2+y2)xyx^2 - xy + y^2 = (x^2 + y^2) - xy gives 208=1220 - 8 = 12. The value is uniquely determined as 12.
Statement (2) supplies component values that combine to form the target expression uniquely.
4
Determine the final Data Sufficiency decision.
Because Statement (1) alone is sufficient and Statement (2) alone is sufficient, the correct choice is that EACH statement ALONE is sufficient.
Both statements independently yield a single, consistent answer to the rephrased question.

Key Concept

Question Stem Rephrasing and Algebraic Identity Simplification in Data Sufficiency
Question 12Question

If xx and yy are real numbers, what is the value of x+yx + y?

(1) x2y+xy2=30x^2 y + xy^2 = 30
(2) x2+y2=19xyx^2 + y^2 = 19 - xy

Show answer & explanation

Answer: Statements (1) and (2) TOGETHER are NOT sufficient.

Answer

Statements (1) and (2) TOGETHER are NOT sufficient to determine a unique value for x+yx + y.
Evaluating both statements together produces the polynomial relation (x+y)319(x+y)30=0(x + y)^3 - 19(x + y) - 30 = 0. Factoring gives (x+y5)(x+y+2)(x+y+3)=0(x + y - 5)(x + y + 2)(x + y + 3) = 0. Each of the three roots (55, 2-2, 3-3) produces real numbers xx and yy satisfying both original equations. Because x+yx + y can take three different values, the two statements together are not sufficient to determine a unique value.

Step-by-Step Solution

1
Analyze Statement (1) independently
Factor Statement (1): x2y+xy2=xy(x+y)=30x^2 y + xy^2 = xy(x + y) = 30.
If (x,y)=(2,3)(x, y) = (2, 3), then xy(x+y)=6(5)=30xy(x + y) = 6(5) = 30, giving x+y=5x + y = 5. If (x,y)=(1,5)(x, y) = (1, 5), then xy(x+y)=5(6)=30xy(x + y) = 5(6) = 30, giving x+y=6x + y = 6. Multiple values exist, so Statement (1) alone is insufficient.
2
Analyze Statement (2) independently
Rearrange Statement (2): x2+y2+xy=19x^2 + y^2 + xy = 19, which equals (x+y)2xy=19(x + y)^2 - xy = 19.
If (x,y)=(3,2)(x, y) = (3, 2), then 32+22+6=193^2 + 2^2 + 6 = 19, giving x+y=5x + y = 5. If (x,y)=(5,3)(x, y) = (-5, 3), then (5)2+32+(15)=19(-5)^2 + 3^2 + (-15) = 19, giving x+y=2x + y = -2. Multiple values exist, so Statement (2) alone is insufficient.
3
Evaluate Statements (1) and (2) together
Express xyxy in terms of S=x+yS = x + y: from Statement (1), xy=30Sxy = \frac{30}{S}; from Statement (2), xy=S219xy = S^2 - 19.
Equating the two expressions for xyxy yields 30S=S219    S319S30=0\frac{30}{S} = S^2 - 19 \implies S^3 - 19S - 30 = 0.
4
Solve the cubic polynomial for S=x+yS = x + y and check for real roots (x,y)(x, y)
S319S30=(S5)(S+2)(S+3)=0S^3 - 19S - 30 = (S - 5)(S + 2)(S + 3) = 0, giving S=5S = 5, S=2S = -2, or S=3S = -3.
For S=5S = 5, xy=6xy = 6, giving real solutions {x,y}={2,3}\{x, y\} = \{2, 3\}. For S=2S = -2, xy=15xy = -15, giving real solutions {x,y}={5,3}\{x, y\} = \{-5, 3\}. For S=3S = -3, xy=10xy = -10, giving real solutions {x,y}={5,2}\{x, y\} = \{-5, 2\}. Since three distinct valid real sums exist, the combined statements are not sufficient.

Key Concept

Non-linear systems of equations may yield multiple distinct real solutions. Two equations in two variables do not guarantee a unique solution in Data Sufficiency unless the system is linear or constrained to a single root.
Question 13Question

If uu and vv are real numbers such that u+v0u + v \neq 0, what is the value of uvu+v\frac{u - v}{u + v}?

(1) u23uv+2v2=0u^2 - 3uv + 2v^2 = 0
(2) 2u25uv+2v2=02u^2 - 5uv + 2v^2 = 0

Show answer & explanation

Answer: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Answer

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
The correct answer is the option stating that both statements together are sufficient, but neither alone is sufficient. Statement (1) yields two possible ratios (u=vu=v giving 0, or u=2vu=2v giving 1/31/3), so it is not sufficient. Statement (2) also yields two possible ratios (u=v/2u=v/2 giving 1/3-1/3, or u=2vu=2v giving 1/31/3), so it is not sufficient. When combined, u=vu=v and u=v/2u=v/2 would require u=v=0u=v=0, which is forbidden by the condition u+v0u+v \neq 0. Therefore, u=2vu=2v is the only valid relation, producing a unique value of 1/31/3.

Step-by-Step Solution

1
Rephrase the target question stem.
Dividing the numerator and denominator of uvu+v\frac{u - v}{u + v} by vv (assuming v0v \neq 0) shows that knowing the ratio uv\frac{u}{v} uniquely determines the value of the expression.
Simplifying the target expression reduces the problem to determining whether a unique ratio uv\frac{u}{v} exists.
2
Evaluate Statement (1) independently.
Factor u23uv+2v2=0u^2 - 3uv + 2v^2 = 0 as (uv)(u2v)=0(u - v)(u - 2v) = 0. This implies u=vu = v or u=2vu = 2v. If u=vu = v, then uvu+v=02v=0\frac{u - v}{u + v} = \frac{0}{2v} = 0. If u=2vu = 2v, then uvu+v=2vv2v+v=v3v=13\frac{u - v}{u + v} = \frac{2v - v}{2v + v} = \frac{v}{3v} = \frac{1}{3}.
Since Statement (1) allows two distinct numerical values (00 and 13\frac{1}{3}), Statement (1) alone is NOT sufficient.
3
Evaluate Statement (2) independently.
Factor 2u25uv+2v2=02u^2 - 5uv + 2v^2 = 0 as (2uv)(u2v)=0(2u - v)(u - 2v) = 0. This implies u=12vu = \frac{1}{2}v or u=2vu = 2v. If u=12vu = \frac{1}{2}v, then uvu+v=12vv12v+v=12v32v=13\frac{u - v}{u + v} = \frac{\frac{1}{2}v - v}{\frac{1}{2}v + v} = \frac{-\frac{1}{2}v}{\frac{3}{2}v} = -\frac{1}{3}. If u=2vu = 2v, then uvu+v=13\frac{u - v}{u + v} = \frac{1}{3}.
Since Statement (2) allows two distinct numerical values (13-\frac{1}{3} and 13\frac{1}{3}), Statement (2) alone is NOT sufficient.
4
Evaluate Statement (1) and Statement (2) combined.
Combine the conditions: Statement (1) requires u=vu = v or u=2vu = 2v; Statement (2) requires u=12vu = \frac{1}{2}v or u=2vu = 2v. Testing u=vu = v in Statement (2) yields 2v25v2+2v2=v2=0    v=02v^2 - 5v^2 + 2v^2 = -v^2 = 0 \implies v = 0, which implies u=0u = 0, but u+v0u + v \neq 0 rules out u=v=0u = v = 0. Testing u=12vu = \frac{1}{2}v in Statement (1) similarly leads to u=v=0u = v = 0. Thus, the only non-zero solution satisfying both equations is u=2vu = 2v, which gives a unique value of 13\frac{1}{3}.
Combining both statements eliminates the ambiguous cases that violate the stem constraint, establishing a unique value.

Key Concept

Homogeneous Quadratic Factoring and Constraint Evaluation in Data Sufficiency
Question 14Question

If uu and vv are real numbers such that uvu \neq v, what is the value of u+vuv\frac{u + v}{u - v}?

(1) u2v2=4(uv)2u^2 - v^2 = 4(u - v)^2
(2) u2+v2=5uvu^2 + v^2 = 5uv

Show answer & explanation

Answer: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Answer

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (1) allows factoring the difference of squares into (uv)(u+v)=4(uv)2(u - v)(u + v) = 4(u - v)^2. Because uvu \neq v, we can divide by (uv)(u - v) to determine directly that u+vuv=4\frac{u + v}{u - v} = 4, which provides a unique value. Statement (2) gives (u+vuv)2=73\left(\frac{u + v}{u - v}\right)^2 = \frac{7}{3}, which yields two possible values (±73\pm\sqrt{\frac{7}{3}}) and is therefore not sufficient. Thus, Statement (1) alone is sufficient, but Statement (2) alone is not.

Step-by-Step Solution

1
Rephrase the target question and examine constraints.
The target expression is u+vuv\frac{u + v}{u - v}. The stem specifies uvu \neq v, so uv0u - v \neq 0, making the fraction well-defined.
Establishing non-zero denominator conditions allows division by (uv)(u - v) when evaluating statements.
2
Evaluate Statement (1) independently.
Rewrite the left side of u2v2=4(uv)2u^2 - v^2 = 4(u - v)^2 as (uv)(u+v)=4(uv)2(u - v)(u + v) = 4(u - v)^2. Since uv0u - v \neq 0, divide both sides by (uv)(u - v) to get u+v=4(uv)u + v = 4(u - v). Divide both sides by (uv)(u - v) again to obtain u+vuv=4\frac{u + v}{u - v} = 4.
This yields a single, definitive numerical value for the target expression. Statement (1) is sufficient.
3
Evaluate Statement (2) independently.
Expand (u+v)2=u2+v2+2uv(u + v)^2 = u^2 + v^2 + 2uv and (uv)2=u2+v22uv(u - v)^2 = u^2 + v^2 - 2uv. Substituting u2+v2=5uvu^2 + v^2 = 5uv gives (u+v)2=7uv(u + v)^2 = 7uv and (uv)2=3uv(u - v)^2 = 3uv. Taking the ratio gives (u+vuv)2=7uv3uv=73\left(\frac{u + v}{u - v}\right)^2 = \frac{7uv}{3uv} = \frac{7}{3} (since uv0uv \neq 0). Taking the square root yields u+vuv=73\frac{u + v}{u - v} = \sqrt{\frac{7}{3}} or 73-\sqrt{\frac{7}{3}}.
Because two distinct numerical values are possible, Statement (2) alone does not yield a unique answer. Statement (2) is not sufficient.

Key Concept

Factoring difference of squares and avoiding degree miscounts in quadratic ratios
Question 15Question

If xx and yy are real numbers, what is the value of x+yx + y?

(1) x2+2xy+y25x5y+6=0x^2 + 2xy + y^2 - 5x - 5y + 6 = 0
(2) xy=2xy = 2

Show answer & explanation

Answer: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Answer

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
The correct response identifies that neither statement alone establishes a single value for x+yx + y, but combining them eliminates x+y=2x + y = 2 because no real numbers xx and yy have a sum of 22 and a product of 22 (discriminant 224(2)=4<02^2 - 4(2) = -4 < 0). Only x+y=3x + y = 3 yields real values for xx and yy (discriminant 324(2)=103^2 - 4(2) = 1 \ge 0). Thus, both statements together are sufficient to determine that x+y=3x + y = 3.

Step-by-Step Solution

1
Analyze Statement (1) by grouping terms in terms of (x+y)(x + y).
Rewrite x2+2xy+y25(x+y)+6=0x^2 + 2xy + y^2 - 5(x + y) + 6 = 0 as (x+y)25(x+y)+6=0(x + y)^2 - 5(x + y) + 6 = 0, which factors into ((x+y)2)((x+y)3)=0((x + y) - 2)((x + y) - 3) = 0. Hence, x+y=2x + y = 2 or x+y=3x + y = 3. Since there are two possible values, Statement (1) alone is NOT sufficient.
Determining whether Statement (1) provides a unique value for the target expression.
2
Analyze Statement (2) independently.
Statement (2) gives xy=2xy = 2. Multiple real pairs satisfy this (e.g., (2,1)x+y=3(2, 1) \Rightarrow x + y = 3 or (1,2)x+y=3(1, 2) \Rightarrow x + y = 3 vs. (2,2)x+y=22(\sqrt{2}, \sqrt{2}) \Rightarrow x + y = 2\sqrt{2}). Thus, Statement (2) alone is NOT sufficient.
Testing whether xy=2xy = 2 alone restricts x+yx + y to a single numerical value.
3
Combine Statement (1) and Statement (2) under the real number constraint.
Let S=x+yS = x + y and P=xy=2P = xy = 2. For xx and yy to be real numbers, they must be the real roots of t2St+P=0t^2 - St + P = 0, requiring discriminant Δ=S24P0\Delta = S^2 - 4P \ge 0.
- Case 1: If S=2S = 2, then Δ=224(2)=4<0\Delta = 2^2 - 4(2) = -4 < 0. No real solutions exist for xx and yy.
- Case 2: If S=3S = 3, then Δ=324(2)=10\Delta = 3^2 - 4(2) = 1 \ge 0. Real solutions exist (e.g., x=2,y=1x = 2, y = 1).
Applying the real-number constraint to eliminate algebraically impossible cases.
4
Conclude total sufficiency.
Only x+y=3x + y = 3 produces real values for xx and yy. Therefore, both statements together uniquely determine x+y=3x + y = 3.
Completing the Data Sufficiency evaluation.

Key Concept

Quadratic expression rephrasing and discriminant constraints for real variable existence in Data Sufficiency
Estimated Time:2m 0s
Question 16Question

If xx and yy are real numbers, what is the value of x2y2x^2 - y^2?

(1) x3y3=26x^3 - y^3 = 26 and x2+xy+y2=13x^2 + xy + y^2 = 13
(2) x+y=4x + y = 4

Show answer & explanation

Answer: BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

Answer

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
Factoring the target expression gives x2y2=(x+y)(xy)x^2 - y^2 = (x + y)(x - y). Statement (1) simplifies via the difference of cubes formula x3y3=(xy)(x2+xy+y2)x^3 - y^3 = (x - y)(x^2 + xy + y^2) to xy=2x - y = 2 and xy=3xy = 3. However, solving for x+yx + y yields (x+y)2=16(x + y)^2 = 16, which gives two solutions (x+y=4x + y = 4 or x+y=4x + y = -4) and thus two values for x2y2x^2 - y^2 (88 or 8-8). Thus, Statement (1) alone is insufficient. Statement (2) gives x+y=4x + y = 4 without constraining xyx - y, making it insufficient alone. Combining both statements provides x+y=4x + y = 4 and xy=2x - y = 2, giving a unique product of 88. Hence, both statements together are sufficient.

Step-by-Step Solution

1
Rephrase the target expression using algebraic identities
x2y2=(x+y)(xy)x^2 - y^2 = (x + y)(x - y)
Determining x2y2x^2 - y^2 requires knowing either the product (x+y)(xy)(x + y)(x - y) or the individual values of x+yx + y and xyx - y.
2
Evaluate Statement (1) independently
Using the difference of cubes identity x3y3=(xy)(x2+xy+y2)x^3 - y^3 = (x - y)(x^2 + xy + y^2), substitute the given values: 26=(xy)(13)    xy=226 = (x - y)(13) \implies x - y = 2. Next, expand (xy)2=x22xy+y2=4(x - y)^2 = x^2 - 2xy + y^2 = 4. Subtracting this from x2+xy+y2=13x^2 + xy + y^2 = 13 gives 3xy=9    xy=33xy = 9 \implies xy = 3. Then (x+y)2=(xy)2+4xy=4+4(3)=16(x + y)^2 = (x - y)^2 + 4xy = 4 + 4(3) = 16, which implies x+y=4x + y = 4 or x+y=4x + y = -4. Thus x2y2=(4)(2)=8x^2 - y^2 = (4)(2) = 8 or (4)(2)=8(-4)(2) = -8.
Because Statement (1) produces two distinct possible values (88 and 8-8), Statement (1) ALONE is NOT sufficient.
3
Evaluate Statement (2) independently
x+y=4x + y = 4
Without any information about xyx - y, x2y2=4(xy)x^2 - y^2 = 4(x - y) can take infinitely many values. Statement (2) ALONE is NOT sufficient.
4
Evaluate Statements (1) and (2) combined
From Statement (1), xy=2x - y = 2. From Statement (2), x+y=4x + y = 4. Multiplying these equations yields x2y2=(x+y)(xy)=(4)(2)=8x^2 - y^2 = (x + y)(x - y) = (4)(2) = 8.
A single, unique numerical value is determined. Therefore, BOTH statements TOGETHER are sufficient.

Key Concept

Algebraic Factoring and Non-Linear System Ambiguity in Data Sufficiency
Estimated Time:2m 0s
Question 17Question

If aa and bb are real numbers, what is the value of (a+b)2(a + b)^2?

(1) a2+b2+4a6b=13a^2 + b^2 + 4a - 6b = -13
(2) ab=6ab = -6

Show answer & explanation

Answer: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Answer

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (1) can be rewritten by completing the square as (a+2)2+(b3)2=0(a + 2)^2 + (b - 3)^2 = 0. Since aa and bb are constrained to be real numbers, (a+2)20(a + 2)^2 \geq 0 and (b3)20(b - 3)^2 \geq 0. The only way their sum can equal 00 is if a=2a = -2 and b=3b = 3. This uniquely determines (a+b)2=(2+3)2=1(a + b)^2 = (-2 + 3)^2 = 1, making Statement (1) alone sufficient. Statement (2) gives ab=6ab = -6, which allows multiple values for (a+b)2(a + b)^2 (e.g., 11 or 2525), making it insufficient. Hence, the option stating that Statement (1) alone is sufficient while Statement (2) alone is not is the correct choice.

Step-by-Step Solution

1
Analyze Statement (1): a2+b2+4a6b=13a^2 + b^2 + 4a - 6b = -13
Rearrange and group terms: (a2+4a)+(b26b)=13(a^2 + 4a) + (b^2 - 6b) = -13. Complete the square for both variables by adding 44 and 99 to both sides: (a2+4a+4)+(b26b+9)=13+4+9(a^2 + 4a + 4) + (b^2 - 6b + 9) = -13 + 4 + 9, which simplifies to (a+2)2+(b3)2=0(a + 2)^2 + (b - 3)^2 = 0.
Grouping and completing the square reveals the sum-of-squares structure.
2
Evaluate the real number constraint on Statement (1)
Because aa and bb are real numbers, (a+2)20(a + 2)^2 \geq 0 and (b3)20(b - 3)^2 \geq 0. The sum of two non-negative terms can equal zero if and only if both terms are independently zero: a+2=0    a=2a + 2 = 0 \implies a = -2 and b3=0    b=3b - 3 = 0 \implies b = 3.
The sum of non-negative real squares equaling zero forces each squared term to be zero.
3
Calculate the target expression using values from Statement (1)
(a+b)2=(2+3)2=(1)2=1(a + b)^2 = (-2 + 3)^2 = (1)^2 = 1. Since this yields a single unique value, Statement (1) ALONE is sufficient.
A unique value for the target expression establishes sufficiency.
4
Analyze Statement (2): ab=6ab = -6
If a=2a = 2 and b=3b = -3, then ab=6ab = -6 and (a+b)2=(23)2=1(a + b)^2 = (2 - 3)^2 = 1. If a=1a = 1 and b=6b = -6, then ab=6ab = -6 and (a+b)2=(16)2=25(a + b)^2 = (1 - 6)^2 = 25. Multiple values are possible.
Testing specific valid cases proves that Statement (2) does not yield a unique result.
5
Conclude Data Sufficiency determination
Statement (1) alone is sufficient, but Statement (2) alone is not sufficient.
Statement (1) produces a unique answer, whereas Statement (2) does not.

Key Concept

Completing the Square and Trivial Inequality for Real Squares in Data Sufficiency
Question 18Question

If xx and yy are non-zero real numbers, what is the value of xy\frac{x}{y}?

(1) x2yxy2=2xyx^2 y - x y^2 = 2xy
(2) x2+y2=5xyx^2 + y^2 = 5xy

Show answer & explanation

Answer: Statements (1) and (2) TOGETHER are NOT sufficient.

Answer

Statements (1) and (2) together are NOT sufficient.
The statement that both statements together are not sufficient is correct because combining Statement (1) (x=y+2x = y + 2) and Statement (2) (x2+y2=5xyx^2 + y^2 = 5xy) leads to a quadratic equation 3y2+6y4=03y^2 + 6y - 4 = 0 with two distinct real roots for yy. Evaluating xy=1+2y\frac{x}{y} = 1 + \frac{2}{y} for both roots yields two distinct possible values, 5+212\frac{5 + \sqrt{21}}{2} and 5212\frac{5 - \sqrt{21}}{2}. Because a unique numerical value cannot be determined, the information provided is not sufficient.

Step-by-Step Solution

1
Evaluate Statement (1) independently.
Simplifies to xy=2    x=y+2x - y = 2 \implies x = y + 2.
Since x,y0x, y \neq 0, xy0xy \neq 0. Dividing x2yxy2=2xyx^2 y - x y^2 = 2xy by xyxy yields xy=2x - y = 2. Thus xy=y+2y=1+2y\frac{x}{y} = \frac{y+2}{y} = 1 + \frac{2}{y}, which varies with yy. Not sufficient.
2
Evaluate Statement (2) independently.
Yields (xy)25(xy)+1=0(\frac{x}{y})^2 - 5(\frac{x}{y}) + 1 = 0.
Dividing x2+y2=5xyx^2 + y^2 = 5xy by y2y^2 gives a quadratic in k=xyk = \frac{x}{y}: k25k+1=0k^2 - 5k + 1 = 0. Solving for kk gives k=5±212k = \frac{5 \pm \sqrt{21}}{2}. Because there are two distinct real solutions for the ratio, Statement (2) alone is not sufficient.
3
Evaluate Statements (1) and (2) combined.
Two distinct pairs of real numbers satisfy both conditions, giving two distinct values for xy\frac{x}{y}.
Substitute x=y+2x = y + 2 into x2+y2=5xyx^2 + y^2 = 5xy: (y+2)2+y2=5y(y+2)    3y2+6y4=0(y+2)^2 + y^2 = 5y(y+2) \implies 3y^2 + 6y - 4 = 0. This gives two real roots for yy: y=3±213y = \frac{-3 \pm \sqrt{21}}{3}. Substituting each yy back into xy=1+2y\frac{x}{y} = 1 + \frac{2}{y} yields xy=5+212\frac{x}{y} = \frac{5 + \sqrt{21}}{2} and xy=5212\frac{x}{y} = \frac{5 - \sqrt{21}}{2}. Since two distinct ratios remain possible, combined statements are not sufficient.

Key Concept

Non-linear systems in Data Sufficiency often result in multiple valid solutions, requiring explicit verification of solution uniqueness rather than assuming two equations with two variables yield a single solution.
Estimated Time:2m 15s
Question 19Question

If pp and qq are real numbers, what is the value of p+qp + q?

(1) p2q+pq2=36p^2 q + p q^2 = 36 and p2+2pq+q2=9p^2 + 2pq + q^2 = 9
(2) p2q2=15p^2 - q^2 = 15

Show answer & explanation

Answer: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Answer

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (1) alone is sufficient because simplifying (p+q)2=9(p+q)^2 = 9 yields two potential values for the sum: p+q=3p+q = 3 or p+q=3p+q = -3. Combining each sum with pq(p+q)=36pq(p+q) = 36 gives corresponding products pq=12pq = 12 and pq=12pq = -12. For real numbers pp and qq, the discriminant S24PS^2 - 4P must be non-negative. The sum p+q=3p+q = 3 gives a negative discriminant 324(12)=393^2 - 4(12) = -39, which yields no real solutions for pp and qq. The sum p+q=3p+q = -3 gives a positive discriminant (3)24(12)=57(-3)^2 - 4(-12) = 57, which yields valid real numbers. Thus, p+qp+q uniquely equals 3-3.

Statement (2) alone is not sufficient because p2q2=(pq)(p+q)=15p^2 - q^2 = (p-q)(p+q) = 15 allows infinitely many different values for p+qp+q depending on pqp-q. Hence, the correct statement selection is that Statement (1) alone is sufficient, but Statement (2) alone is not sufficient.

Step-by-Step Solution

1
Rephrase and analyze Statement (1) algebraically.
From p2+2pq+q2=9p^2 + 2pq + q^2 = 9, we have (p+q)2=9(p + q)^2 = 9, which implies p+q=3p + q = 3 or p+q=3p + q = -3. Factor the second equation: p2q+pq2=pq(p+q)=36p^2 q + p q^2 = pq(p + q) = 36.
Factoring exposes the sum S=p+qS = p + q and product P=pqP = pq structure of the algebraic system.
2
Evaluate the real number constraint for Case 1 (p+q=3p + q = 3) in Statement (1).
If p+q=3p + q = 3, then pq(3)=36    pq=12pq(3) = 36 \implies pq = 12. For real numbers pp and qq with sum 33 and product 1212, they must be real roots of t23t+12=0t^2 - 3t + 12 = 0. The discriminant is Δ=(3)24(1)(12)=948=39<0\Delta = (-3)^2 - 4(1)(12) = 9 - 48 = -39 < 0.
A negative discriminant means no real numbers pp and qq exist for which p+q=3p + q = 3 and pq=12pq = 12. Thus, p+q=3p + q = 3 is impossible.
3
Evaluate the real number constraint for Case 2 (p+q=3p + q = -3) in Statement (1).
If p+q=3p + q = -3, then pq(3)=36    pq=12pq(-3) = 36 \implies pq = -12. The corresponding quadratic equation for pp and qq is t2+3t12=0t^2 + 3t - 12 = 0, with discriminant Δ=324(1)(12)=57>0\Delta = 3^2 - 4(1)(-12) = 57 > 0. Real solutions exist.
Since a positive discriminant guarantees real solutions for pp and qq, p+qp + q must uniquely equal 3-3. Therefore, Statement (1) alone is sufficient.
4
Evaluate Statement (2) independently.
p2q2=15    (pq)(p+q)=15p^2 - q^2 = 15 \implies (p - q)(p + q) = 15. For example, if p=4,q=1p = 4, q = 1, then p+q=5p + q = 5. If p=8,q=7p = 8, q = 7, then p+q=15p + q = 15.
Without knowing pqp - q, infinitely many pairs of real numbers satisfy p2q2=15p^2 - q^2 = 15 with different sums p+qp + q. Statement (2) alone is not sufficient.

Key Concept

Evaluating non-linear algebraic systems in Data Sufficiency using real variable discriminant constraints
Question 20Question

If aa and bb are positive real numbers, what is the value of a2+b2a^2 + b^2?

(1) a4b4=5(a2b2)a^4 - b^4 = 5(a^2 - b^2)
(2) ab=6ab = 6 and a+b=5a + b = 5

Show answer & explanation

Answer: Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

Answer

Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
Statement (1) simplifies to (a2b2)(a2+b25)=0(a^2 - b^2)(a^2 + b^2 - 5) = 0, which allows a2+b2=5a^2 + b^2 = 5 when aba \neq b, but allows infinitely many values for a2+b2a^2 + b^2 when a=ba = b. Hence, Statement (1) alone is insufficient. Statement (2) provides a+b=5a + b = 5 and ab=6ab = 6, allowing us to use (a+b)2=a2+b2+2ab(a + b)^2 = a^2 + b^2 + 2ab to find a2+b2=2512=13a^2 + b^2 = 25 - 12 = 13 uniquely. Therefore, Statement (2) alone is sufficient.

Step-by-Step Solution

1
Analyze Statement (1) algebraically.
Factor the left side as (a2b2)(a2+b2)=5(a2b2)(a^2 - b^2)(a^2 + b^2) = 5(a^2 - b^2). Rearranging yields (a2b2)(a2+b25)=0(a^2 - b^2)(a^2 + b^2 - 5) = 0.
Dividing by (a2b2)(a^2 - b^2) is valid only if aba \neq b.
2
Evaluate sufficiency of Statement (1).
If aba \neq b, then a2+b2=5a^2 + b^2 = 5. However, if a=b>0a = b > 0, then a2b2=0a^2 - b^2 = 0, which makes the equation true for any positive value of aa, meaning a2+b2=2a2a^2 + b^2 = 2a^2 can take infinitely many values (e.g., if a=b=1a=b=1, a2+b2=2a^2+b^2=2; if a=b=3a=b=3, a2+b2=18a^2+b^2=18). Thus, a unique value cannot be determined.
Multiple possible values mean Statement (1) is not sufficient.
3
Evaluate sufficiency of Statement (2).
Use the algebraic identity (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2. Substituting a+b=5a + b = 5 and ab=6ab = 6 gives 52=a2+2(6)+b25^2 = a^2 + 2(6) + b^2, so 25=a2+b2+12    a2+b2=1325 = a^2 + b^2 + 12 \implies a^2 + b^2 = 13.
This determines a single, unique numerical value for a2+b2a^2 + b^2.
4
Conclude overall sufficiency.
Statement (1) is NOT sufficient, but Statement (2) IS sufficient.
Statement (2) alone resolves the target question.

Key Concept

Algebraic Equations and Systems in Data Sufficiency
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