Table Analysis

63 questions

All types63 Multiple choice20 Multiple select3 True / False27 Numeric9 Matching4

The table below displays Q2 2026 performance data for seven autonomous cargo drone fleets operated by a logistics provider:

Fleet ID	Total Flight Hours	On-Time Delivery Rate (%)	Payload Capacity (kg)	Operating Cost per Km ($)
Alpha-1	420	94.5%	150	12.40
Beta-2	550	91.0%	200	15.80
Gamma-3	310	96.0%	120	10.50
Delta-4	600	88.5%	250	18.20
Epsilon-5	480	93.0%	180	14.10
Zeta-6	390	97.5%	140	11.80
Eta-7	510	89.0%	220	16.50

Consider the following three statements:

I. The median Operating Cost per Km among fleets with a Payload Capacity of at least 150 kg is greater than $15.00.
II. Among fleets with an On-Time Delivery Rate above 92.0%, the fleet with the lowest Total Flight Hours also has the lowest Operating Cost per Km.
III. The mean Total Flight Hours for fleets with a Payload Capacity under 180 kg is greater than 400 hours.

Which of the statements evaluate to True based on the table?

Only Statement I is true

Only Statement II is true

Exactly Statements I and II are true

Exactly Statements II and III are true

All three statements (I, II, and III) are true

Show answer & explanation

Answer: Exactly Statements I and II are true

Answer

Statements I and II are True, while Statement III is False.

Evaluating each statement systematically shows that Statement I is True because the sorted costs for eligible fleets are

12.40,

14.10,

15.80,

16.50,

18.20, giving a median of

15.80 (which exceeds

15.00). Statement II is True because Gamma-3 meets the delivery rate threshold (> 92.0%) and holds both the minimum flight hours (310) and minimum operating cost (

10.50) among those fleets. Statement III is False because the filtered fleets (Alpha-1, Gamma-3, Zeta-6) have a mean flight hour of 373.33 hours, which is less than 400 hours. Thus, exactly Statements I and II are true.

Step-by-Step Solution

Evaluate Statement I by filtering and sorting Operating Cost per Km for fleets with Payload Capacity

\ge 150\text{ kg}

Fleets meeting the condition are Alpha-1 (150 kg), Beta-2 (200 kg), Delta-4 (250 kg), Epsilon-5 (180 kg), and Eta-7 (220 kg). Their operating costs sorted from lowest to highest are

12.40,

14.10,

15.80,

16.50,

18.20. The median of these 5 values is the 3rd value, which is

15.80. Since

15.80 >

15.00, Statement I is TRUE.

Finding the median of an odd number of items requires ordering the subset values and taking the middle element.

Evaluate Statement II by filtering fleets with On-Time Delivery Rate

> 92.0\%

Fleets meeting the condition are Alpha-1 (94.5%), Gamma-3 (96.0%), Epsilon-5 (93.0%), and Zeta-6 (97.5%). Among these 4 fleets, Gamma-3 has the lowest Total Flight Hours (310 hours) and also the lowest Operating Cost per Km ($10.50). Therefore, Statement II is TRUE.

Cross-column multi-condition filtering verifies both the minimum flight hours and minimum operating cost within the subset.

Evaluate Statement III by calculating the mean Total Flight Hours for fleets with Payload Capacity

< 180\text{ kg}

Fleets with Payload Capacity strictly less than 180 kg are Gamma-3 (120 kg), Zeta-6 (140 kg), and Alpha-1 (150 kg). (Epsilon-5 is excluded as its payload is exactly 180 kg). Their flight hours are 310, 390, and 420. Mean =

\frac{310 + 390 + 420}{3} = \frac{1120}{3} \approx 373.33\text{ hours}

. Since

373.33 < 400

, Statement III is FALSE.

Computing the arithmetic mean of the correctly filtered subset shows it is below the threshold of 400 hours.

Key Concept

Multi-Statement Boolean Evaluation on structured tables involving subset filtering, median calculation, and conditional verification.

Estimated Time:2m 0s

Question 62Question →

The table below presents annual production and resource consumption metrics for four semiconductor fabrication plants in 2025.

Fab Facility	Silicon Wafers Processed (in thousands)	Solvent Used per Wafer (in mL)	Total Electricity Consumed (in MWh)
Fab Alpha	450	800	3,600
Fab Beta	600	500	4,200
Fab Gamma	250	1,200	2,750
Fab Delta	800	450	5,200

Note: $1\text{ kiloliter (kL)} = 1,000\text{ liters (L)} = 1,000,000\text{ milliliters (mL)}$ .

Based on the table, what was the total volume of solvent used by Fab Alpha in 2025, expressed in kiloliters (kL)?

Show answer & explanation

Answer: 360

Answer

The total volume of solvent used by Fab Alpha in 2025 was 360 kL.

To find the total solvent used by Fab Alpha in kiloliters, first account for the scale factor in the wafer column header: Fab Alpha processed 450 thousand wafers, which is

450 \times 1,000 = 450,000

wafers. Next, calculate the volume in milliliters:

450,000 \text{ wafers} \times 800 \text{ mL/wafer} = 360,000,000 \text{ mL}

. Finally, convert to kiloliters by dividing by

1,000,000

(

1 \text{ kL} = 1,000,000 \text{ mL}

), which gives

360 \text{ kL}

Step-by-Step Solution

Extract wafer volume with scale multiplier

Fab Alpha processed 450,000 wafers.

The table column header specifies 'in thousands', requiring a multiplier of 1,000.

Calculate total solvent volume in milliliters

Total solvent volume = 360,000,000 mL.

Multiply 450,000 wafers by 800 mL per wafer.

Convert volume to target unit (kiloliters)

360 kL.

Divide 360,000,000 mL by 1,000,000 mL per kL.

Key Concept

Unit Conversion and Scale Interpretation

Question 63Question →

The table below details operational and environmental metrics recorded in 2025 across 10 international container hub ports:

Port ID	Container Throughput (M TEUs)	Average Berth Dwell Time (hrs)	Automated Crane Ratio (%)	Carbon Intensity (g CO₂/ton-km)
Port Alpha	14.2	34.5	18	28.4
Port Beta	8.5	31.0	25	26.2
Port Gamma	22.1	28.2	35	24.5
Port Delta	11.0	26.0	42	23.0
Port Epsilon	18.7	23.5	50	21.8
Port Zeta	6.4	21.0	58	20.1
Port Eta	25.3	19.2	64	18.9
Port Theta	16.0	17.5	72	17.5
Port Iota	29.8	15.0	80	16.0
Port Kappa	12.6	13.2	88	14.2

If the table is sorted in ascending order by Automated Crane Ratio (%), which of the following statements correctly describes a cross-column trend observed across all ten ports?

As the Automated Crane Ratio increases, both the Average Berth Dwell Time and the Carbon Intensity decrease monotonically across all ten ports.

As the Automated Crane Ratio increases, Container Throughput increases monotonically across all ten ports.

As the Automated Crane Ratio increases, Average Berth Dwell Time decreases, but Carbon Intensity shows no consistent direction across the ports.

Average Berth Dwell Time increases as Carbon Intensity decreases across all ten ports.

Container Throughput and Average Berth Dwell Time exhibit a strict inverse correlation across all ten ports.

Show answer & explanation

Answer: As the Automated Crane Ratio increases, both the Average Berth Dwell Time and the Carbon Intensity decrease monotonically across all ten ports.

Answer

As the Automated Crane Ratio increases, both the Average Berth Dwell Time and the Carbon Intensity decrease monotonically across all ten ports.

When the table is ordered by Automated Crane Ratio (%) from lowest (18%) to highest (88%), the values for Average Berth Dwell Time continuously drop from 34.5 to 13.2 hours, and Carbon Intensity continuously drops from 28.4 to 14.2 g CO₂/ton-km. Therefore, both metrics decrease monotonically as automation increases.

Step-by-Step Solution

Identify the primary sort column and order the table elements accordingly.

The Automated Crane Ratio values in ascending order are: 18% (Alpha), 25% (Beta), 35% (Gamma), 42% (Delta), 50% (Epsilon), 58% (Zeta), 64% (Eta), 72% (Theta), 80% (Iota), and 88% (Kappa).

The question specifies sorting the data by Automated Crane Ratio (%) in ascending order.

Examine the corresponding row values for Average Berth Dwell Time (hrs).

Dwell times in sorted order: 34.5, 31.0, 28.2, 26.0, 23.5, 21.0, 19.2, 17.5, 15.0, 13.2 hours. Each value is strictly smaller than the preceding value.

To verify if Average Berth Dwell Time displays a monotonic trend across all ten data points.

Examine the corresponding row values for Carbon Intensity (g CO₂/ton-km).

Carbon Intensity values in sorted order: 28.4, 26.2, 24.5, 23.0, 21.8, 20.1, 18.9, 17.5, 16.0, 14.2. Each value is strictly smaller than the preceding value.

To verify if Carbon Intensity displays a monotonic trend parallel to Berth Dwell Time.

Check Container Throughput (M TEUs) for any monotonic trend.

Throughput values in sorted order: 14.2, 8.5, 22.1, 11.0, 18.7, 6.4, 25.3, 16.0, 29.8, 12.6. This sequence increases and decreases non-monotonically.

To evaluate and rule out statements asserting a consistent trend in Container Throughput.

Key Concept

Cross-Column Correlation and Trend Analysis

Estimated Time:2m 0s

PreviousPage 4 / 4

Table Analysis

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

Answer

Step-by-Step Solution

Key Concept

Common Mistakes