Question

Difficulty: HardLinear Inequalities and Absolute Value

If xx is an integer that satisfies both ∣4x−5∣≤13|4x - 5| \le 13 and 2x−1−3≤−1\frac{2x - 1}{-3} \le -1, what is the sum of all possible values of xx?

  1. A
    -7
  2. B
    0
  3. C
    7
  4. 9Answer
  5. E
    14

Answer

9
Solving the absolute value inequality ∣4x−5∣≤13|4x - 5| \le 13 yields −13≤4x−5≤13-13 \le 4x - 5 \le 13, which simplifies to −2≤x≤4.5-2 \le x \le 4.5. Next, solving 2x−1−3≤−1\frac{2x - 1}{-3} \le -1 requires multiplying both sides by −3-3 and reversing the inequality sign, giving 2x−1≥32x - 1 \ge 3, which simplifies to x≥2x \ge 2. Combining −2≤x≤4.5-2 \le x \le 4.5 and x≥2x \ge 2 for integer xx gives the set {2,3,4}\{2, 3, 4\}. The sum of these values is 2+3+4=92 + 3 + 4 = 9.

Step-by-Step Solution

1
Solve the absolute value inequality ∣4x−5∣≤13|4x - 5| \le 13
-13 \le 4x - 5 \le 13 \implies -8 \le 4x \le 18 \implies -2 \le x \le 4.5
An absolute value inequality ∣u∣≤k|u| \le k unfolds into the compound inequality −k≤u≤k-k \le u \le k.
2
Solve the linear inequality 2x−1−3≤−1\frac{2x - 1}{-3} \le -1
2x - 1 \ge 3 \implies 2x \ge 4 \implies x \ge 2
Multiplying or dividing both sides of an inequality by a negative number reverses the direction of the inequality sign.
3
Find the intersection of the two solution sets for integer xx
x \in \{2, 3, 4\}
The integers satisfying both −2≤x≤4.5-2 \le x \le 4.5 and x≥2x \ge 2 are 2, 3, and 4.
4
Calculate the sum of the possible integer values
2 + 3 + 4 = 9
Summing the valid integer solutions yields the final requested answer.

Key Concept

Linear Inequalities and Absolute Value
Estimated Time:2m 0s
Rate this question