Question

Difficulty: Very hardSet Theory Concepts and Venn Diagrams

A technology institute surveyed a cohort of 300300 software engineers regarding their proficiency in three programming paradigms: Functional (FF), Object-Oriented (OO), and Concurrent (CC). Every surveyed engineer is proficient in at least one of these three paradigms. The ratio of the total number of engineers proficient in FF, OO, and CC is 5:6:45 : 6 : 4, respectively. Furthermore, exactly 20%20\% of the engineers proficient in FF are proficient in all three paradigms. If exactly 5454 engineers are proficient in both FF and OO, 4848 are proficient in both OO and CC, and 3030 are proficient in both FF and CC, how many engineers in the cohort are proficient in exactly one programming paradigm?

  1. A
    96
  2. B
    141
  3. 222Answer
  4. D
    273
  5. E
    78

Answer

222 engineers are proficient in exactly one programming paradigm.
Using the Principle of Inclusion-Exclusion for three sets, FOC=F+O+C(FO+OC+FC)+FOC|F \cup O \cup C| = |F| + |O| + |C| - (|F \cap O| + |O \cap C| + |F \cap C|) + |F \cap O \cap C|. Substituting F=5k|F|=5k, O=6k|O|=6k, C=4k|C|=4k, FOC=k|F \cap O \cap C|=k, and the total cohort 300300 gives 300=16k132300 = 16k - 132, yielding k=27k = 27. Consequently, the triple intersection is 2727. Decomposing into disjoint regions: FF only =78= 78, OO only =87= 87, and CC only =57= 57. Summing these gives 78+87+57=22278 + 87 + 57 = 222.

Step-by-Step Solution

1
Set up algebraic representations for the set sizes using the given ratio.
Let F=5k|F| = 5k, O=6k|O| = 6k, and C=4k|C| = 4k for some positive constant kk.
The total proficiencies follow the ratio 5:6:45:6:4.
2
Express the triple intersection FOC|F \cap O \cap C| in terms of kk.
FOC=0.20×F=0.20×5k=k|F \cap O \cap C| = 0.20 \times |F| = 0.20 \times 5k = k.
Exactly 20% of engineers proficient in FF are proficient in all three paradigms.
3
Apply the Principle of Inclusion-Exclusion for three sets to solve for kk.
FOC=F+O+C(FO+OC+FC)+FOC    300=5k+6k+4k(54+48+30)+k    300=16k132    16k=432    k=27|F \cup O \cup C| = |F| + |O| + |C| - (|F \cap O| + |O \cap C| + |F \cap C|) + |F \cap O \cap C| \implies 300 = 5k + 6k + 4k - (54 + 48 + 30) + k \implies 300 = 16k - 132 \implies 16k = 432 \implies k = 27.
Every engineer is proficient in at least one paradigm, so FOC=300|F \cup O \cap C| = 300.
4
Calculate the total size of each set and each exclusive intersection region.
F=135|F| = 135, O=162|O| = 162, C=108|C| = 108, and FOC=27|F \cap O \cap C| = 27.
Exclusively FO=5427=27F \cap O = 54 - 27 = 27.
Exclusively OC=4827=21O \cap C = 48 - 27 = 21.
Exclusively FC=3027=3F \cap C = 30 - 27 = 3.
Subtracting the triple intersection from pairwise intersections yields the two-set-only regions.
5
Determine the number of engineers proficient in exactly one paradigm.
Only F=135(27+3+27)=78F = 135 - (27 + 3 + 27) = 78.
Only O=162(27+21+27)=87O = 162 - (27 + 21 + 27) = 87.
Only C=108(3+21+27)=57C = 108 - (3 + 21 + 27) = 57.
Total exactly one = 78+87+57=22278 + 87 + 57 = 222.
Subtracting all overlapping regions from each total set size gives the single-category populations.

Key Concept

Three-set Principle of Inclusion-Exclusion and Venn Diagram region decomposition.
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