Question

Difficulty: MediumProbability of Independent, Dependent, and Mutually Exclusive Events

A quality control inspector evaluates a batch of 1616 precision components. Exactly 1010 of the components meet all engineering specifications, while 66 have minor surface defects. If the inspector randomly selects 22 components from the batch one after another without replacement, what is the probability that both selected components meet all engineering specifications?

Answer: 0.375

Answer

The probability that both selected components meet all engineering specifications is 0.3750.375 (or 38\frac{3}{8}).
Since the components are selected without replacement, the outcome of the second draw depends on the outcome of the first draw. The probability of selecting a qualifying component first is 1016\frac{10}{16}. Given that a qualifying component was drawn first, 99 qualifying components remain out of 1515 total components. The joint probability of both events occurring is 1016×915=90240=38=0.375\frac{10}{16} \times \frac{9}{15} = \frac{90}{240} = \frac{3}{8} = 0.375.

Step-by-Step Solution

1
Determine the probability of selecting a component meeting specifications on the first draw.
P(E1)=1016=58P(E_1) = \frac{10}{16} = \frac{5}{8}
There are 1010 qualifying components out of 1616 total components.
2
Determine the conditional probability of selecting a second component meeting specifications, given that the first component selected also met specifications.
P(E2E1)=915=35P(E_2 \mid E_1) = \frac{9}{15} = \frac{3}{5}
Because sampling is done without replacement, 99 qualifying components remain out of 1515 total remaining components.
3
Apply the multiplication rule for dependent events to calculate the probability of both events occurring.
P(E1E2)=P(E1)×P(E2E1)=58×35=38=0.375P(E_1 \cap E_2) = P(E_1) \times P(E_2 \mid E_1) = \frac{5}{8} \times \frac{3}{5} = \frac{3}{8} = 0.375
For dependent events, the joint probability is the product of the first event's probability and the conditional probability of the second event.

Key Concept

Probability of Dependent Events without Replacement
Estimated Time:1m 15s
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