Question

Difficulty: MediumRatios, Rates, and Proportions

An agricultural facility uses three conveyor belts—XX, YY, and ZZ—to transfer harvested grain into a storage silo. Working together at their respective constant rates, Belt XX and Belt YY can fill the empty silo in 6 hours6\text{ hours}. Working together at their respective constant rates, Belt YY and Belt ZZ can fill the empty silo in 8 hours8\text{ hours}. If Belt XX operates at twice the rate of Belt ZZ, how many hours would it take Belt YY working alone at its constant rate to fill the empty silo?

  1. A
    10 hours10\text{ hours}
  2. 12 hours12\text{ hours}Answer
  3. C
    16 hours16\text{ hours}
  4. D
    18 hours18\text{ hours}
  5. E
    24 hours24\text{ hours}

Answer

12 hours12\text{ hours}
The correct answer is 12 hours12\text{ hours}. Subtracting the combined rate equation for Belts YY and ZZ (rY+rZ=1/8r_Y + r_Z = 1/8) from the equation for Belts XX and YY (rX+rY=1/6r_X + r_Y = 1/6) yields rXrZ=1/24r_X - r_Z = 1/24. Since Belt XX works at twice the rate of Belt ZZ (rX=2rZr_X = 2r_Z), substituting gives rZ=1/24r_Z = 1/24. Substituting rZr_Z back into rY+rZ=1/8r_Y + r_Z = 1/8 gives rY=1/81/24=1/12r_Y = 1/8 - 1/24 = 1/12. Therefore, Belt YY operating alone takes 12 hours12\text{ hours} to fill the silo.

Step-by-Step Solution

1
Define the work rates of each conveyor belt.
Let rXr_X, rYr_Y, and rZr_Z be the fraction of the silo filled per hour by Belts XX, YY, and ZZ, respectively.
Establishing rates per unit of time allows linear combination of work performed.
2
Set up equations based on the given combined times and rate relationships.
rX+rY=16r_X + r_Y = \frac{1}{6}, rY+rZ=18r_Y + r_Z = \frac{1}{8}, and rX=2rZr_X = 2r_Z.
Combined rates equal the reciprocal of the total time required for combined work.
3
Subtract the second equation from the first to isolate rXrZr_X - r_Z.
(rX+rY)(rY+rZ)=1618    rXrZ=4324=124(r_X + r_Y) - (r_Y + r_Z) = \frac{1}{6} - \frac{1}{8} \implies r_X - r_Z = \frac{4 - 3}{24} = \frac{1}{24}.
Eliminating rYr_Y gives a direct linear relationship between rXr_X and rZr_Z.
4
Substitute rX=2rZr_X = 2r_Z into rXrZ=124r_X - r_Z = \frac{1}{24} to solve for rZr_Z.
2rZrZ=124    rZ=1242r_Z - r_Z = \frac{1}{24} \implies r_Z = \frac{1}{24}.
Determines the individual rate of Belt ZZ.
5
Substitute rZ=124r_Z = \frac{1}{24} back into the equation rY+rZ=18r_Y + r_Z = \frac{1}{8} to find rYr_Y.
rY=18124=324124=224=112r_Y = \frac{1}{8} - \frac{1}{24} = \frac{3}{24} - \frac{1}{24} = \frac{2}{24} = \frac{1}{12}.
Finds the individual rate of Belt YY.
6
Calculate the time required for Belt YY alone.
\text{Time} = \frac{1}{r_Y} = 12\text{ hours}.
The time to complete one full job is the reciprocal of the individual rate.

Key Concept

Work Rates and Combined Rate Equations
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