Question

Difficulty: EasyPythagorean Theorem and Special Right Triangles

A 1010-foot straight ladder leans against a vertical wall on flat horizontal ground. If the bottom of the ladder is 66 feet away from the base of the wall, how high up the wall, in feet, does the top of the ladder reach?

Answer: 8 feet

Answer

The top of the ladder reaches 88 feet up the wall.
Applying the Pythagorean theorem a2+b2=c2a^2 + b^2 = c^2 with hypotenuse c=10c = 10 and ground leg a=6a = 6 gives 62+b2=1026^2 + b^2 = 10^2, which simplifies to 36+b2=10036 + b^2 = 100, so b2=64b^2 = 64 and b=8b = 8 feet.

Step-by-Step Solution

1
Set up the right triangle relationship using the Pythagorean theorem.
a2+b2=c2a^2 + b^2 = c^2, where a=6a = 6 and c=10c = 10.
The ladder forms the hypotenuse of a right triangle with the vertical wall and horizontal ground.
2
Substitute the known values into the formula and solve for bb.
62+b2=102    36+b2=100    b2=64    b=86^2 + b^2 = 10^2 \implies 36 + b^2 = 100 \implies b^2 = 64 \implies b = 8.
Subtracting 3636 from 100100 gives 6464, and taking the positive square root yields the vertical height.

Key Concept

Applying the Pythagorean Theorem (a2+b2=c2a^2 + b^2 = c^2) to find an unknown leg length in a right triangle context.
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