Question

Difficulty: EasyEstimation, Rounding, and Sequences

A sequence of numbers begins with t1=4t_1 = 4. For all integers n2n \geq 2, each term is defined by tn=3tn12t_n = 3t_{n-1} - 2. What is the value of t5t_5?

Answer: 244

Answer

The 5th term of the sequence, t5t_5, is equal to 244.
Applying the recursive relation tn=3tn12t_n = 3t_{n-1} - 2 step-by-step starting from t1=4t_1 = 4 gives t2=10t_2 = 10, t3=28t_3 = 28, t4=82t_4 = 82, and finally t5=244t_5 = 244.

Step-by-Step Solution

1
Find the second term, t2t_2, using t1=4t_1 = 4.
t2=3(4)2=122=10t_2 = 3(4) - 2 = 12 - 2 = 10
Substitute n=2n = 2 into the recursive rule tn=3tn12t_n = 3t_{n-1} - 2.
2
Find the third term, t3t_3, using t2=10t_2 = 10.
t3=3(10)2=302=28t_3 = 3(10) - 2 = 30 - 2 = 28
Substitute n=3n = 3 into the recursive rule.
3
Find the fourth term, t4t_4, using t3=28t_3 = 28.
t4=3(28)2=842=82t_4 = 3(28) - 2 = 84 - 2 = 82
Substitute n=4n = 4 into the recursive rule.
4
Find the fifth term, t5t_5, using t4=82t_4 = 82.
t5=3(82)2=2462=244t_5 = 3(82) - 2 = 246 - 2 = 244
Substitute n=5n = 5 into the recursive rule.

Key Concept

Evaluating terms in a recursively defined sequence
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