Question

Difficulty: MediumRatios, Rates, and Proportions

Working alone at their respective constant rates, Machine AA can complete a production order in 6 hours6\text{ hours}, Machine BB in 8 hours8\text{ hours}, and Machine CC in 12 hours12\text{ hours}. All three machines start working together on the order at 9:00 AM. At 10:00 AM, Machine AA breaks down and stops working, while Machines BB and CC continue working together at their constant rates until the order is completed. At what time will the production order be completed?

  1. A
    11:40 AM
  2. B
    12:00 PM
  3. 1:00 PMAnswer
  4. D
    1:48 PM
  5. E
    2:12 PM

Answer

The production order will be completed at 1:00 PM.
The option specifying 1:00 PM is correct because during the first hour (9:00 AM to 10:00 AM), all three machines work together and complete 16+18+112=38\frac{1}{6} + \frac{1}{8} + \frac{1}{12} = \frac{3}{8} of the job. This leaves 58\frac{5}{8} of the job remaining at 10:00 AM. Machines B and C work together at a rate of 18+112=524\frac{1}{8} + \frac{1}{12} = \frac{5}{24} of the job per hour. Dividing the remaining work (58\frac{5}{8}) by this combined rate (524\frac{5}{24}) gives exactly 3 hours. Adding 3 hours to 10:00 AM yields 1:00 PM.

Step-by-Step Solution

1
Calculate individual work rates for each machine.
Machine A rate = 16\frac{1}{6} order/hr, Machine B rate = 18\frac{1}{8} order/hr, Machine C rate = 112\frac{1}{12} order/hr.
Work rate is defined as job completed per unit of time.
2
Calculate the work completed by all three machines from 9:00 AM to 10:00 AM (1 hour).
Combined rate = 16+18+112=4+3+224=924=38\frac{1}{6} + \frac{1}{8} + \frac{1}{12} = \frac{4 + 3 + 2}{24} = \frac{9}{24} = \frac{3}{8} of the order.
All three machines work together for exactly 1 hour.
3
Determine the remaining fraction of the order after 10:00 AM.
Remaining work = 138=581 - \frac{3}{8} = \frac{5}{8} of the order.
Subtract completed work from the total work (1 whole order).
4
Calculate the combined rate of Machines B and C.
Combined rate of B and C = 18+112=3+224=524\frac{1}{8} + \frac{1}{12} = \frac{3 + 2}{24} = \frac{5}{24} order/hr.
Machine A stops, leaving only B and C working.
5
Calculate the additional time needed to complete the remaining work.
Time = 5/85/24=58×245=3 hours\frac{5/8}{5/24} = \frac{5}{8} \times \frac{24}{5} = 3\text{ hours}.
Divide remaining work by the combined rate of the remaining active machines.
6
Add the additional time to the breakdown time (10:00 AM).
Completion time = 10:00 AM + 3 hours = 1:00 PM.
The remaining work begins at 10:00 AM when Machine A breaks down.

Key Concept

Combined Work Rates and Staggered Work Times
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