Question

Difficulty: MediumQuadrilaterals and Polygons

In the xyxy-plane, quadrilateral ABCDABCD has vertices A(0,0)A(0, 0), B(6,0)B(6, 0), C(8,4)C(8, 4), and D(2,4)D(2, 4). Which of the following statements must be true? Select all such statements.

  1. Quadrilateral ABCDABCD is a parallelogram.Answer
  2. The area of quadrilateral ABCDABCD is 2424.Answer
  3. The diagonals ACAC and BDBD bisect each other at the point (4,2)(4, 2).Answer
  4. D
    The length of diagonal ACAC is equal to the length of diagonal BDBD.
  5. E
    The diagonals ACAC and BDBD are perpendicular to each other.

Answer

The correct statements are that quadrilateral ABCDABCD is a parallelogram, its area is 2424, and its diagonals bisect each other at (4,2)(4, 2).
Quadrilateral ABCDABCD is a parallelogram because both pairs of opposite sides are congruent and parallel (AB=DC=6AB = DC = 6 along the horizontal line, and AD=BC=20AD = BC = \sqrt{20}). The area is base times height, which is 6×4=246 \times 4 = 24. The diagonals bisect each other at their common midpoint (4,2)(4, 2).

Step-by-Step Solution

1
Determine side lengths and slopes to classify the quadrilateral
Side ABAB is horizontal with length 66; side DCDC is horizontal with length 66. Side ADAD has components (2,4)(2,4) and length 20\sqrt{20}; side BCBC has components (2,4)(2,4) and length 20\sqrt{20}. Since opposite sides are parallel and congruent, ABCDABCD is a parallelogram.
To verify if the quadrilateral is a parallelogram.
2
Calculate the area of the quadrilateral
Area = base×height=6×4=24\text{base} \times \text{height} = 6 \times 4 = 24.
To evaluate the area statement.
3
Find the midpoints and lengths of diagonals ACAC and BDBD
Midpoint of AC=(4,2)AC = (4, 2) and midpoint of BD=(4,2)BD = (4, 2), so they bisect each other. Length AC=82+42=80=45AC = \sqrt{8^2 + 4^2} = \sqrt{80} = 4\sqrt{5}, and length BD=(4)2+42=32=42BD = \sqrt{(-4)^2 + 4^2} = \sqrt{32} = 4\sqrt{2}.
To check diagonal bisection and length equality.
4
Determine the slopes of the diagonals to check for perpendicularity
Slope of AC=48=12AC = \frac{4}{8} = \frac{1}{2}; slope of BD=44=1BD = \frac{4}{-4} = -1. Product of slopes =12×(1)=121= \frac{1}{2} \times (-1) = -\frac{1}{2} \neq -1, so they are not perpendicular.
To verify whether the diagonals intersect at right angles.

Key Concept

Properties of quadrilaterals in the coordinate plane, including parallelogram identification, area calculation, midpoint theorem for diagonals, and perpendicular slope test.
Estimated Time:1m 30s
Rate this question