Question

Difficulty: HardLinear Equations in One Variable
If xx satisfies the linear equation
3(x−2)4−x−53=2x+16+2\frac{3(x - 2)}{4} - \frac{x - 5}{3} = \frac{2x + 1}{6} + 2
what is the value of 2x−52x - 5?
  1. 43Answer
  2. B
    24
  3. C
    123
  4. D
    -1
  5. E
    51

Answer

43
The correct answer is obtained by clearing denominators with the least common denominator 12, yielding 9(x−2)−4(x−5)=2(2x+1)+249(x - 2) - 4(x - 5) = 2(2x + 1) + 24. Expanding and simplifying gives 5x+2=4x+265x + 2 = 4x + 26, which isolates x=24x = 24. Substituting x=24x = 24 into 2x−52x - 5 results in 2(24)−5=432(24) - 5 = 43.

Step-by-Step Solution

1
Clear the denominators by multiplying every term in the equation by the least common multiple of 4, 3, and 6, which is 12.
12⋅3(x−2)4−12⋅x−53=12⋅2x+16+12⋅2  ⟹  9(x−2)−4(x−5)=2(2x+1)+2412 \cdot \frac{3(x - 2)}{4} - 12 \cdot \frac{x - 5}{3} = 12 \cdot \frac{2x + 1}{6} + 12 \cdot 2 \implies 9(x - 2) - 4(x - 5) = 2(2x + 1) + 24
Eliminating fractions simplifies the linear equation into standard polynomial form.
2
Distribute the constants through the parentheses, taking careful note of negative signs.
9x−18−4x+20=4x+2+249x - 18 - 4x + 20 = 4x + 2 + 24
Parentheses must be removed to collect like variable and constant terms.
3
Combine like terms on both sides of the equation.
5x+2=4x+265x + 2 = 4x + 26
Consolidating terms on each side allows for isolating the variable.
4
Isolate xx on one side of the equation.
5x−4x=26−2  ⟹  x=245x - 4x = 26 - 2 \implies x = 24
Subtracting 4x4x and 2 from both sides solves directly for xx.
5
Evaluate the target expression 2x−52x - 5 using x=24x = 24.
2(24)−5=48−5=432(24) - 5 = 48 - 5 = 43
The question requests the value of 2x−52x - 5, not xx alone.

Key Concept

Solving multi-step linear equations in one variable with fractional terms and evaluating algebraic expressions.
Estimated Time:2m 0s
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