Question

Difficulty: EasyAlgebraic Exponents and Radicals

If xx is a positive real number, which of the following is equivalent to the expression (x3)2x4x8\frac{(x^3)^2 \cdot x^{-4}}{\sqrt{x^8}}?

  1. x2x^{-2}Answer
  2. B
    x2x^2
  3. C
    x3x^{-3}
  4. D
    x4x^{-4}
  5. E
    x0x^0

Answer

The simplified expression is equivalent to x2x^{-2}.
Applying the rules of exponents systematically yields (x3)2=x6(x^3)^2 = x^6 in the numerator, which combines with x4x^{-4} to give x2x^2. The denominator x8\sqrt{x^8} simplifies to x8/2=x4x^{8/2} = x^4. Dividing x2x^2 by x4x^4 gives x24=x2x^{2-4} = x^{-2}.

Step-by-Step Solution

1
Simplify the power raised to a power in the numerator.
(x3)2=x32=x6(x^3)^2 = x^{3 \cdot 2} = x^6
When raising a power to a power, multiply the exponents: (am)n=amn(a^m)^n = a^{m \cdot n}.
2
Multiply the terms in the numerator.
x6x4=x6+(4)=x2x^6 \cdot x^{-4} = x^{6 + (-4)} = x^2
When multiplying exponential expressions with the same base, add the exponents: aman=am+na^m \cdot a^n = a^{m+n}.
3
Simplify the radical in the denominator.
x8=(x8)12=x82=x4\sqrt{x^8} = (x^8)^{\frac{1}{2}} = x^{\frac{8}{2}} = x^4
Taking the square root of a non-negative term is equivalent to raising it to the power of 12\frac{1}{2}.
4
Divide the numerator by the denominator.
\frac{x^2}{x^4} = x^{2 - 4} = x^{-2}
When dividing exponential expressions with the same base, subtract the denominator exponent from the numerator exponent: \frac{a^m}{a^n} = a^{m-n}.

Key Concept

Laws of Exponents and Radical Simplification
Estimated Time:45s
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