Question

Difficulty: MediumMeasures of Central Tendency (Mean, Median, Mode)

A research laboratory conducted 66 experimental trials to measure the duration, in milliseconds, of a specific chemical reaction. The durations recorded for 55 of the trials were 240240, 215215, 260260, 225225, and 245245. If the median duration of all 66 trials was 235235 milliseconds, what was the duration, in milliseconds, of the 6th trial?

Answer: 230 milliseconds

Answer

230
For a dataset with 6 numbers, the median is the arithmetic mean of the 3rd and 4th numbers in ascending order. Arranging the 5 given numbers gives 215,225,240,245,260215, 225, 240, 245, 260. Since the target median is 235235, the sum of the two middle numbers must be 235×2=470235 \times 2 = 470. Placing x=230x = 230 into the dataset yields the ordered set 215,225,230,240,245,260215, 225, 230, 240, 245, 260, where the 3rd and 4th numbers are 230230 and 240240. Their mean is (230+240)/2=235(230 + 240) / 2 = 235, which matches the given median.

Step-by-Step Solution

1
Order the 5 given numbers from least to greatest
The sorted list of known values is 215,225,240,245,260215, 225, 240, 245, 260.
Calculating or using median requires ordering the data points.
2
Express the median condition for an even number of data points (n=6n = 6)
Median=3rd value+4th value2=235\text{Median} = \frac{\text{3rd value} + \text{4th value}}{2} = 235, so 3rd value+4th value=470\text{3rd value} + \text{4th value} = 470.
For an even number of values, the median is the average of the two middle numbers.
3
Determine the position and value of the unknown 6th trial xx
If x225x \le 225, the 3rd and 4th values would be 225225 and 240240 (median 232.5232.5). If x245x \ge 245, the 3rd and 4th values would be 240240 and 245245 (median 242.5242.5). Thus, xx must lie between 225225 and 240240.
Analyzing boundary conditions places xx as the 3rd value and 240240 as the 4th value.
4
Solve for xx
x+240=470    x=230x + 240 = 470 \implies x = 230.
The sum of the two middle values must equal 470470 to yield a median of 235235.

Key Concept

Finding a missing value in a dataset given the median of an even number of observations.
Rate this question