Question

Difficulty: EasyProperties of Integers and Divisibility

If xx is any integer, which of the following expressions must be divisible by 22?

  1. A
    x2+1x^2 + 1
  2. x2+x+4x^2 + x + 4Answer
  3. C
    x3+2x+1x^3 + 2x + 1
  4. D
    2x2+x+32x^2 + x + 3
  5. E
    x2+3x+1x^2 + 3x + 1

Answer

The expression x2+x+4x^2 + x + 4 must be divisible by 22 for all integer values of xx.
The expression x2+x+4x^2 + x + 4 can be rewritten as x(x+1)+4x(x + 1) + 4. For any integer xx, either xx or x+1x + 1 is even, so their product x(x+1)x(x + 1) is always even (a multiple of 22). Adding 44 (which is also even) to an even number always yields an even number. Therefore, x2+x+4x^2 + x + 4 is divisible by 22 for all integer values of xx.

Step-by-Step Solution

1
Rewrite the expression by factoring out xx from the first two terms.
x2+x+4=x(x+1)+4x^2 + x + 4 = x(x + 1) + 4
Grouping terms isolates the product of two consecutive integers.
2
Analyze the parity of the product x(x+1)x(x + 1).
Because xx and x+1x + 1 are consecutive integers, one of them must be even, making the product x(x+1)x(x + 1) an even integer.
The product of any integer and its immediate successor is always even.
3
Add 44 to the even product x(x+1)x(x + 1).
The sum of an even integer and an even integer (44) is always an even integer.
Adding an even integer to an even integer preserves divisibility by 22.

Key Concept

Parity of consecutive integer products and integer divisibility rules
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