Question

Difficulty: EasyExponents, Powers, and Square Roots

If 2x×43=292^x \times 4^3 = 2^9, what is the value of xx?

Answer: 3

Answer

The value of xx is 3.
By rewriting 434^3 as (22)3=26(2^2)^3 = 2^6, the equation becomes 2x26=292^x \cdot 2^6 = 2^9. Applying the product rule gives 2x+6=292^{x+6} = 2^9, which simplifies to x+6=9x + 6 = 9, yielding x=3x = 3.

Step-by-Step Solution

1
Convert all terms to base 2
43=(22)3=22×3=264^3 = (2^2)^3 = 2^{2 \times 3} = 2^6
To apply exponent rules, expressions should share a common base.
2
Apply product rule of exponents to the left side of the equation
2x×26=2x+62^x \times 2^6 = 2^{x+6}
When multiplying exponential terms with the same base, add their exponents: aman=am+na^m \cdot a^n = a^{m+n}.
3
Equate the exponents from both sides
x+6=9x + 6 = 9
Since the bases are identical and non-zero, the exponents must be equal.
4
Solve the linear equation for xx
x=3x = 3
Subtract 6 from both sides of the equation.

Key Concept

Combining exponential terms with equal bases using power rules (aman=am+na^m \cdot a^n = a^{m+n} and (am)n=amn(a^m)^n = a^{mn}).
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