Question

Difficulty: HardSet Theory Concepts and Venn Diagrams

A software security audit evaluated 500500 open-source repositories for three specific vulnerability types: SQL Injection (SS), Cross-Site Scripting (XX), and Buffer Overflow (BB). Exactly 8080 repositories had none of these vulnerabilities. The audit revealed the following data:

- 220220 repositories contained SQL Injection vulnerabilities.
- 190190 repositories contained Cross-Site Scripting vulnerabilities.
- 210210 repositories contained Buffer Overflow vulnerabilities.
- 7575 repositories contained both SQL Injection and Cross-Site Scripting vulnerabilities.
- 8080 repositories contained both Cross-Site Scripting and Buffer Overflow vulnerabilities.
- 3030 repositories contained all three vulnerability types.

How many of the audited repositories contained Buffer Overflow vulnerabilities ONLY?

  1. A
    5555
  2. 8585Answer
  3. C
    100100
  4. D
    130130
  5. E
    155155

Answer

85 repositories contained Buffer Overflow vulnerabilities only.
The total number of repositories containing at least one vulnerability is 500−80=420500 - 80 = 420. Using the inclusion-exclusion formula ∣S∪X∪B∣=∣S∣+∣X∣+∣B∣−(∣S∩X∣+∣X∩B∣+∣S∩B∣)+∣S∩X∩B∣|S \cup X \cup B| = |S| + |X| + |B| - (|S \cap X| + |X \cap B| + |S \cap B|) + |S \cap X \cap B|, we substitute the known values: 420=220+190+210−(75+80+∣S∩B∣)+30420 = 220 + 190 + 210 - (75 + 80 + |S \cap B|) + 30. Solving gives 420=650−155−∣S∩B∣420 = 650 - 155 - |S \cap B|, so ∣S∩B∣=75|S \cap B| = 75. The repositories containing Buffer Overflow ONLY are given by subtracting the overlapping regions from the total Buffer Overflow set: ∣B∣−(∣S∩B∣ only)−(∣X∩B∣ only)−∣S∩X∩B∣=210−(75−30)−(80−30)−30=210−45−50−30=85|B| - (|S \cap B| \text{ only}) - (|X \cap B| \text{ only}) - |S \cap X \cap B| = 210 - (75 - 30) - (80 - 30) - 30 = 210 - 45 - 50 - 30 = 85.

Step-by-Step Solution

1
Calculate the total number of repositories containing at least one vulnerability
∣S∪X∪B∣=500−80=420|S \cup X \cup B| = 500 - 80 = 420
The total population is 500 and 80 repositories have no vulnerabilities.
2
Apply the 3-Set Inclusion-Exclusion Principle to determine the sum of pairwise intersections
∣S∩X∣+∣X∩B∣+∣S∩B∣=230|S \cap X| + |X \cap B| + |S \cap B| = 230
From ∣S∪X∪B∣=∣S∣+∣X∣+∣B∣−(∣S∩X∣+∣X∩B∣+∣S∩B∣)+∣S∩X∩B∣|S \cup X \cup B| = |S| + |X| + |B| - (|S \cap X| + |X \cap B| + |S \cap B|) + |S \cap X \cap B|, we get 420=220+190+210−∑∣intersections∣+30420 = 220 + 190 + 210 - \sum |\text{intersections}| + 30, so ∑∣intersections∣=650−420=230\sum |\text{intersections}| = 650 - 420 = 230.
3
Find the missing pairwise intersection ∣S∩B∣|S \cap B|
∣S∩B∣=75|S \cap B| = 75
Since ∣S∩X∣=75|S \cap X| = 75 and ∣X∩B∣=80|X \cap B| = 80, we have 75+80+∣S∩B∣=23075 + 80 + |S \cap B| = 230, which yields ∣S∩B∣=75|S \cap B| = 75.
4
Calculate the number of repositories with Buffer Overflow ONLY
∣B only∣=85|B \text{ only}| = 85
Subtract the exclusive two-set overlaps and the three-set overlap from ∣B∣|B|: ∣B only∣=∣B∣−(∣S∩B∣−∣S∩X∩B∣)−(∣X∩B∣−∣S∩X∩B∣)−∣S∩X∩B∣=210−(75−30)−(80−30)−30=210−45−50−30=85|B \text{ only}| = |B| - (|S \cap B| - |S \cap X \cap B|) - (|X \cap B| - |S \cap X \cap B|) - |S \cap X \cap B| = 210 - (75 - 30) - (80 - 30) - 30 = 210 - 45 - 50 - 30 = 85.

Key Concept

Three-Set Inclusion-Exclusion Principle and Venn Diagram Region Analysis
Rate this question