Question

Difficulty: MediumProperties of Integers and Divisibility

When the positive integer nn is divided by 1212, the remainder is 77. What is the remainder when n2+3n+5n^2 + 3n + 5 is divided by 1212?

  1. A
    11
  2. 33Answer
  3. C
    44
  4. D
    77
  5. E
    1515

Answer

The remainder when n2+3n+5n^2 + 3n + 5 is divided by 1212 is 33.
The correct answer is obtained by replacing nn with its remainder 77 modulo 1212 in the expression n2+3n+5n^2 + 3n + 5. Evaluating gives 72+3(7)+5=49+21+5=757^2 + 3(7) + 5 = 49 + 21 + 5 = 75. Dividing 7575 by 1212 yields 66 with a remainder of 33.

Step-by-Step Solution

1
Express nn in terms of its quotient and remainder modulo 1212.
n=12q+7n = 12q + 7 for some non-negative integer qq, meaning n7(mod12)n \equiv 7 \pmod{12}.
By the division algorithm, any integer nn leaving a remainder of 77 when divided by 1212 can be represented as 12q+712q + 7.
2
Substitute n7(mod12)n \equiv 7 \pmod{12} into the polynomial expression n2+3n+5n^2 + 3n + 5.
n2+3n+572+3(7)+5(mod12)n^2 + 3n + 5 \equiv 7^2 + 3(7) + 5 \pmod{12}.
Properties of modular arithmetic allow direct substitution of equivalent remainders into polynomial expressions.
3
Evaluate the arithmetic expression.
72+3(7)+5=49+21+5=757^2 + 3(7) + 5 = 49 + 21 + 5 = 75.
Compute the total numeric value before finding the final remainder modulo 1212.
4
Divide the total sum by 1212 to find the final remainder.
75=12×6+375 = 12 \times 6 + 3, so the remainder is 33.
A remainder modulo 1212 must be an integer in the range from 00 to 1111.

Key Concept

Properties of Remainders and Modular Substitution
Estimated Time:1m 15s
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