Question

Difficulty: MediumRatios, Rates, and Proportions

A laboratory technician prepares a chemical mixture containing water, ethanol, and acid in the volume ratio 5:3:25 : 3 : 2, respectively. After 12 liters12\text{ liters} of pure ethanol are added to the mixture, the ratio of the volume of water to the volume of ethanol becomes 1:11 : 1. What was the total volume, in liters, of the chemical mixture before the extra ethanol was added?

  1. 60 liters60\text{ liters}Answer
  2. B
    48 liters48\text{ liters}
  3. C
    72 liters72\text{ liters}
  4. D
    18 liters18\text{ liters}
  5. E
    30 liters30\text{ liters}

Answer

60 liters60\text{ liters}
The initial ratio of water, ethanol, and acid is 5:3:25 : 3 : 2, which means the original amounts can be expressed as 5x5x, 3x3x, and 2x2x liters, respectively, giving a total initial volume of 10x10x liters. Adding 12 liters12\text{ liters} of ethanol increases the ethanol amount to 3x+123x + 12, while water remains 5x5x. Since the new ratio of water to ethanol is 1:11 : 1, we set 5x=3x+125x = 3x + 12, which solves to 2x=122x = 12 and x=6x = 6. The original total volume is therefore 10(6)=60 liters10(6) = 60\text{ liters}.

Step-by-Step Solution

1
Define initial volumes using a common ratio multiplier xx
Water volume =5x= 5x, Ethanol volume =3x= 3x, Acid volume =2x= 2x, and Total initial volume =5x+3x+2x=10x= 5x + 3x + 2x = 10x.
Ratios represent relative parts of a whole, so multiplying each term by xx gives the actual quantities.
2
Express the new volumes after adding 12 liters12\text{ liters} of pure ethanol
New Ethanol volume =3x+12= 3x + 12, while Water volume remains 5x5x.
Ethanol is increased by 12 liters12\text{ liters}, whereas the amount of water remains unchanged.
3
Set up an equation using the new water-to-ethanol ratio of 1:11 : 1
5x=3x+12    2x=12    x=65x = 3x + 12 \implies 2x = 12 \implies x = 6.
A ratio of 1:11 : 1 means the volumes of water and ethanol are equal.
4
Calculate the original total volume of the mixture
Total initial volume =10x=10(6)=60 liters= 10x = 10(6) = 60\text{ liters}.
Substituting x=6x = 6 back into the original total volume expression 10x10x yields the required initial volume.

Key Concept

Multi-component ratio modification and proportional equivalence
Estimated Time:1m 30s
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