Question

Difficulty: EasyAlgebraic Word Problems and Modeling

A reservoir initially contains 4,8004,800 gallons of water. A drainage pump operates at a constant rate of 120120 gallons per minute to empty the reservoir. How many minutes of continuous pumping will it take for the amount of water remaining in the reservoir to be reduced to 1,2001,200 gallons?

  1. A
    1010
  2. B
    2525
  3. 3030Answer
  4. D
    4040
  5. E
    5050

Answer

30 minutes
To find the time needed for 1,2001,200 gallons to remain, subtract 1,2001,200 from the initial 4,8004,800 gallons to determine that 3,6003,600 gallons of water must be removed. Dividing the 3,6003,600 gallons by the drainage rate of 120120 gallons per minute gives exactly 3030 minutes.

Step-by-Step Solution

1
Calculate the total volume of water that must be drained from the reservoir.
4,800 gallons1,200 gallons=3,600 gallons4,800 \text{ gallons} - 1,200 \text{ gallons} = 3,600 \text{ gallons}
The question asks for the time until 1,2001,200 gallons remain, so the amount removed is the difference between the starting volume and ending volume.
2
Set up the linear rate equation to solve for elapsed time tt in minutes.
Rate×t=Volume Drained    120t=3,600\text{Rate} \times t = \text{Volume Drained} \implies 120t = 3,600
The rate of drainage is constant at 120120 gallons per minute.
3
Solve for tt.
t=3,600120=30 minutest = \frac{3,600}{120} = 30 \text{ minutes}
Dividing total gallons to drain by the rate gives the required time.

Key Concept

Linear Modeling and Distance-Rate-Time / Work-Rate Relationships
Estimated Time:1m 0s
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