Linear Equations in One Variable

42 questions

Question 41Question

A digital archive charges an annual subscription fee of $120\$120, which includes 5050 free document downloads per year. For each additional document downloaded beyond the first 5050, the archive charges a flat rate of $1.50\$1.50. If a research group paid a total of $231\$231 to the archive last year, how many total documents did the research group download?

Show answer & explanation

Answer: 124

Answer

The total number of documents downloaded by the research group last year was 124.
Subtracting the base subscription fee of 120fromthetotalpaymentof120 from the total payment of 231 leaves 111spentstrictlyonextradownloads.Dividing111 spent strictly on extra downloads. Dividing 111 by the $1.50 per-document rate yields 74 extra downloads. Adding the 50 included free downloads gives a total of 124 documents downloaded.

Step-by-Step Solution

1
Define the linear equation representing total cost.
120+1.50(x50)=231120 + 1.50(x - 50) = 231, where xx represents the total number of documents downloaded.
The base subscription fee is 120,andtheperdocumentrateof120, and the per-document rate of 1.50 applies only to documents in excess of the initial 50 free documents.
2
Isolate the variable term by subtracting the base subscription fee from both sides.
1.50(x50)=231120=1111.50(x - 50) = 231 - 120 = 111
This determines the portion of the total cost that resulted strictly from additional downloads.
3
Solve for the number of additional documents (x50)(x - 50).
x50=1111.50=74x - 50 = \frac{111}{1.50} = 74
Dividing the extra cost of 111bytheperdocumentrateof111 by the per-document rate of 1.50 gives the exact count of extra downloads.
4
Add the initial 50 free documents to find the total document count xx.
x=74+50=124x = 74 + 50 = 124
The question asks for the total documents downloaded, which combines the 50 free downloads and the 74 additional paid downloads.

Key Concept

Linear Equations in One Variable
Estimated Time:1m 30s
Question 42Question

If xx is the solution to the linear equation 4x33x+24=5x6\frac{4x - 3}{3} - \frac{x + 2}{4} = \frac{5x}{6}, which of the following statements about xx must be true? Select all such statements.

Select all that apply

Show answer & explanation

Answer: xx is a multiple of 3; 2x5>62x - 5 > 6; x25x=6x^2 - 5x = 6

Answer

The statements establishing that xx is a multiple of 3, that 2x5>62x - 5 > 6, and that x25x=6x^2 - 5x = 6 are all true.
Solving the linear equation yields x=6x = 6. Substituting x=6x = 6 into each statement shows that xx is a multiple of 3 (6=3×26 = 3 \times 2), 2x5>62x - 5 > 6 evaluates to 7>67 > 6, and x25x=6x^2 - 5x = 6 evaluates to 3630=636 - 30 = 6. All three statements are correct.

Step-by-Step Solution

1
Clear denominators by multiplying both sides by the least common multiple.
12(4x33x+24)=12(5x6)    4(4x3)3(x+2)=2(5x)12 \cdot \left(\frac{4x - 3}{3} - \frac{x + 2}{4}\right) = 12 \cdot \left(\frac{5x}{6}\right) \implies 4(4x - 3) - 3(x + 2) = 2(5x)
The least common multiple of 3, 4, and 6 is 12.
2
Distribute factors and combine like terms.
16x123x6=10x    13x18=10x16x - 12 - 3x - 6 = 10x \implies 13x - 18 = 10x
Distributing 3-3 into (x+2)(x + 2) yields 3x6-3x - 6.
3
Isolate xx on one side of the equation.
13x10x=18    3x=18    x=613x - 10x = 18 \implies 3x = 18 \implies x = 6
Subtract 10x10x and add 18 to isolate the variable term.
4
Evaluate each given statement using x=6x = 6.
Statement 1: 66 is a multiple of 3 (True). Statement 2: 2(6)5=7>62(6) - 5 = 7 > 6 (True). Statement 3: 625(6)=66^2 - 5(6) = 6 (True). Statement 4: 6 is prime (False). Statement 5: 6<56 < 5 (False).
Test each option against the calculated solution x=6x = 6.

Key Concept

Linear Equations in One Variable
Estimated Time:1m 30s
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