A solid block of mass 0.5\text{ kg} is completely immersed in water and displaces 0.2\text… — JAMB UTME

A solid block of mass $0.5\text{ kg}$ is completely immersed in water and displaces $0.2\text{ kg}$ of water. What is the magnitude of the upthrust exerted by the water on the block? (Take $g = 10\text{ m/s}^2$ )

$2\text{ N}$ Answer
B
$3\text{ N}$
C
$5\text{ N}$
D
$7\text{ N}$

Answer

The magnitude of the upthrust exerted on the block is

2\text{ N}

By Archimedes' principle, the buoyant force (upthrust) acting on a submerged object equals the weight of the liquid displaced by the object. Since the mass of displaced water is

0.2\text{ kg}

and

g = 10\text{ m/s}^2

, the weight of the displaced water is

0.2\text{ kg} \times 10\text{ m/s}^2 = 2\text{ N}

Step-by-Step Solution

Identify Archimedes' Principle

Upthrust (

U

) is equal to the weight of the fluid displaced by the immersed body.

Archimedes' principle states that the buoyant force on a submerged body equals the weight of the fluid it displaces.

Calculate the weight of the displaced water

W_{\text{displaced}} = m_{\text{water}} \times g = 0.2\text{ kg} \times 10\text{ m/s}^2 = 2\text{ N}

Weight is calculated as mass multiplied by acceleration due to gravity.

State the upthrust

U = 2\text{ N}

The upthrust is directly equal to the weight of the displaced water.

Key Concept

Archimedes' Principle and Upthrust

Estimated Time:45s

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