Question

Difficulty: HardPercentage Composition and Percentage Purity Calculations
A 3.25 g3.25\text{ g} sample of impure zinc granules reacts completely with excess dilute tetraoxosulfate(VI) acid according to the equation:
Zn(s)+H2SO4(aq)ZnSO4(aq)+H2(g)\text{Zn(s)} + \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{ZnSO}_4\text{(aq)} + \text{H}_2\text{(g)}
If 896 cm3896\text{ cm}^3 of hydrogen gas is collected at STP, calculate the percentage purity of the zinc sample. [Zn=65; Molar volume of gas at STP=22.4 dm3mol1][\text{Zn} = 65\text{; Molar volume of gas at STP} = 22.4\text{ dm}^3\text{mol}^{-1}]

Answer: 80 %

Answer

80%
The volume of hydrogen gas produced at STP (896 cm3=0.896 dm3896\text{ cm}^3 = 0.896\text{ dm}^3) corresponds to 0.04 mol0.04\text{ mol} of H2\text{H}_2. Based on the 1:11:1 stoichiometric reaction between zinc and tetraoxosulfate(VI) acid, 0.04 mol0.04\text{ mol} of pure zinc was present in the sample. The mass of pure zinc is 0.04 mol×65 g/mol=2.60 g0.04\text{ mol} \times 65\text{ g/mol} = 2.60\text{ g}. Dividing this pure mass by the total sample mass of 3.25 g3.25\text{ g} and multiplying by 100%100\% yields a percentage purity of 80%80\%.

Step-by-Step Solution

1
Convert the collected volume of hydrogen gas from cm³ to dm³
Volume of H2=896 cm31000 cm3/dm3=0.896 dm3\text{Volume of H}_2 = \frac{896\text{ cm}^3}{1000\text{ cm}^3/\text{dm}^3} = 0.896\text{ dm}^3
Molar gas volume is given in dm³/mol, so gas volume must be expressed in dm³.
2
Calculate the amount in moles of hydrogen gas produced at STP
Moles of H2=0.896 dm322.4 dm3mol1=0.04 mol\text{Moles of H}_2 = \frac{0.896\text{ dm}^3}{22.4\text{ dm}^3\text{mol}^{-1}} = 0.04\text{ mol}
Number of moles of gas at STP equals volume divided by molar volume.
3
Determine the moles and mass of pure zinc that reacted
Moles of pure Zn=0.04 mol\text{Moles of pure Zn} = 0.04\text{ mol}; Mass of pure Zn=0.04 mol×65 g/mol=2.60 g\text{Mass of pure Zn} = 0.04\text{ mol} \times 65\text{ g/mol} = 2.60\text{ g}
The reaction stoichiometry shows a 1:1 mole ratio between Zn and H₂.
4
Calculate the percentage purity of the zinc sample
Percentage Purity=(2.60 g3.25 g)×100%=80%\text{Percentage Purity} = \left( \frac{2.60\text{ g}}{3.25\text{ g}} \right) \times 100\% = 80\%
Percentage purity is the ratio of pure substance mass to total sample mass expressed as a percentage.

Key Concept

Percentage purity determination via gas volume stoichiometry at STP
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