Question

Difficulty: Very hardRadioactive Decay Law and Half-life

A sample of a radioactive nuclide has a half-life of 4 hours4\text{ hours}. What is the ratio of the number of nuclei that have decayed to the number of undecayed nuclei remaining after a total elapsed time of 16 hours16\text{ hours}?

  1. 15:115 : 1Answer
  2. B
    1:151 : 15
  3. C
    15:1615 : 16
  4. D
    7:17 : 1

Answer

The ratio of decayed nuclei to remaining undecayed nuclei is 15:115 : 1.
In an elapsed time of 16 hours16\text{ hours} (which is 44 half-lives), the remaining undecayed portion of the sample is (1/2)4=1/16(1/2)^4 = 1/16 of the original amount. Consequently, 11/16=15/161 - 1/16 = 15/16 of the nuclei have decayed. The ratio of decayed nuclei to remaining nuclei is (15/16):(1/16)=15:1(15/16) : (1/16) = 15 : 1.

Step-by-Step Solution

1
Determine the number of half-lives (nn) that have elapsed.
n=tT1/2=16 hours4 hours=4 half-livesn = \frac{t}{T_{1/2}} = \frac{16\text{ hours}}{4\text{ hours}} = 4\text{ half-lives}.
The number of half-lives is the total time divided by the half-life duration.
2
Calculate the fraction of original nuclei remaining undecayed (N/N0N/N_0).
NN0=(12)n=(12)4=116\frac{N}{N_0} = \left(\frac{1}{2}\right)^n = \left(\frac{1}{2}\right)^4 = \frac{1}{16}.
After nn half-lives, the remaining fraction is (1/2)n(1/2)^n.
3
Find the fraction of original nuclei that have decayed (Ndecayed/N0N_{\text{decayed}}/N_0).
\frac{N_{\text{decayed}}}{N_0} = 1 - \frac{N}{N_0} = 1 - \frac{1}{16} = \frac{15}{16}.
Decayed fraction equals total initial fraction (1) minus the undecayed fraction.
4
Compute the ratio of decayed nuclei to remaining undecayed nuclei.
\text{Ratio} = \frac{N_{\text{decayed}}}{N} = \frac{15/16}{1/16} = 15 : 1.
The question asks for the ratio of decayed nuclei to remaining undecayed nuclei.

Key Concept

Radioactive Decay Law and Half-life calculations involving ratios of decayed versus remaining quantities.
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