Question

Difficulty: MediumMatrices and Determinants

If P=(3124)P = \begin{pmatrix} 3 & 1 \\ 2 & 4 \end{pmatrix} and Q=(1205)Q = \begin{pmatrix} 1 & -2 \\ 0 & 5 \end{pmatrix}, what is the product matrix PQPQ?

  1. (31216)\begin{pmatrix} 3 & -1 \\ 2 & 16 \end{pmatrix}Answer
  2. B
    (32020)\begin{pmatrix} 3 & -2 \\ 0 & 20 \end{pmatrix}
  3. C
    (171020)\begin{pmatrix} -1 & -7 \\ 10 & 20 \end{pmatrix}
  4. D
    (311216)\begin{pmatrix} 3 & 11 \\ 2 & 16 \end{pmatrix}

Answer

The product matrix PQPQ is (31216)\begin{pmatrix} 3 & -1 \\ 2 & 16 \end{pmatrix}.
The matrix containing elements 3, -1 in the top row and 2, 16 in the bottom row correctly applies the row-by-column multiplication rule for matrices PP and QQ.

Step-by-Step Solution

1
Set up the row-by-column matrix multiplication PQPQ
PQ=(3124)(1205)PQ = \begin{pmatrix} 3 & 1 \\ 2 & 4 \end{pmatrix} \begin{pmatrix} 1 & -2 \\ 0 & 5 \end{pmatrix}
Matrix multiplication requires computing dot products of rows of the first matrix with columns of the second matrix.
2
Calculate the first row elements of the product matrix
Row 1, Column 1: 3(1)+1(0)=3+0=33(1) + 1(0) = 3 + 0 = 3; Row 1, Column 2: 3(2)+1(5)=6+5=13(-2) + 1(5) = -6 + 5 = -1
Multiply elements of Row 1 of PP by corresponding elements of Columns 1 and 2 of QQ and sum them.
3
Calculate the second row elements of the product matrix
Row 2, Column 1: 2(1)+4(0)=2+0=22(1) + 4(0) = 2 + 0 = 2; Row 2, Column 2: 2(2)+4(5)=4+20=162(-2) + 4(5) = -4 + 20 = 16
Multiply elements of Row 2 of PP by corresponding elements of Columns 1 and 2 of QQ and sum them.
4
Assemble the resulting 2×22 \times 2 matrix
PQ=(31216)PQ = \begin{pmatrix} 3 & -1 \\ 2 & 16 \end{pmatrix}
Combine all computed entry values into matrix form.

Key Concept

Matrix Multiplication (Row-by-Column Rule)
Estimated Time:1m 30s
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