Question

Difficulty: HardMeasurement of Length and Measuring Instruments

A micrometer screw gauge has a pitch of 0.5 mm0.5\text{ mm} and 5050 divisions on its circular thimble scale. When its anvil and spindle are fully brought together without any object, the zero mark of the thimble scale lies 44 divisions past the main scale index line in the tightening direction (a positive zero error). When the wall thickness of a hollow metal pipe is measured with this micrometer, the main scale reading is 3.5 mm3.5\text{ mm} and the 32nd32\text{nd} thimble division aligns with the index line. If the outer diameter of the pipe is separately measured to be 25.40 mm25.40\text{ mm}, what is the corrected inner diameter of the metal pipe in millimeters?

Answer: 17.84 mm

Answer

17.84 mm
The least count of the micrometer screw gauge is 0.5 mm50=0.01 mm\frac{0.5\text{ mm}}{50} = 0.01\text{ mm}. The observed wall thickness is 3.5 mm+(32×0.01 mm)=3.82 mm3.5\text{ mm} + (32 \times 0.01\text{ mm}) = 3.82\text{ mm}. Accounting for the positive zero error of +0.04 mm+0.04\text{ mm} gives a true wall thickness of 3.82 mm0.04 mm=3.78 mm3.82\text{ mm} - 0.04\text{ mm} = 3.78\text{ mm}. Subtracting twice the wall thickness from the outer diameter yields the inner diameter: 25.40 mm2(3.78 mm)=17.84 mm25.40\text{ mm} - 2(3.78\text{ mm}) = 17.84\text{ mm}.

Step-by-Step Solution

1
Calculate the least count (precision) of the micrometer screw gauge
Least count = 0.01 mm
Least count is defined as pitch divided by total circular scale divisions: 0.5 mm / 50 = 0.01 mm.
2
Determine the observed wall thickness from the instrument readings
Observed thickness = 3.82 mm
Observed reading = Main scale reading + (Thimble division * Least count) = 3.5 mm + (32 * 0.01 mm) = 3.82 mm.
3
Correct the observed thickness for positive zero error
Corrected wall thickness = 3.78 mm
Positive zero error (+0.04 mm) must be subtracted from the observed reading: 3.82 mm - 0.04 mm = 3.78 mm.
4
Calculate the corrected inner diameter of the hollow pipe
Inner diameter = 17.84 mm
The inner diameter equals the outer diameter minus twice the wall thickness: 25.40 mm - 2(3.78 mm) = 25.40 mm - 7.56 mm = 17.84 mm.

Key Concept

Measurement of length, micrometer zero error correction, and geometry of hollow cylinders
Estimated Time:2m 30s
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