Question

Difficulty: EasySound Waves, Echoes, Pitch, Loudness, and Quality

A girl stands at a specific distance from a flat vertical wall and claps her hands once. If she hears the echo 0.4 s0.4\text{ s} later, what is her distance from the wall in meters? (Take the speed of sound in air as 340 m/s340\text{ m/s})

Answer: 68 m

Answer

The distance of the girl from the wall is 68 m68\text{ m}.
An echo involves the sound traveling to the reflecting surface and returning to the source, covering a total distance of 2d2d. Using 2d=v×t2d = v \times t, we obtain d=340×0.42=68 md = \frac{340 \times 0.4}{2} = 68\text{ m}.

Step-by-Step Solution

1
Identify the given values from the problem statement.
Time for echo t=0.4 st = 0.4\text{ s}, speed of sound v=340 m/sv = 340\text{ m/s}.
An echo is a reflected sound wave that travels to the wall and back, completing a round trip.
2
Apply the echo calculation formula.
d=v×t2d = \frac{v \times t}{2}
The total distance traveled by the sound is 2d2d. Thus, the one-way distance dd to the reflecting surface is half of the total distance.
3
Substitute the values and calculate the distance.
d=340×0.42=68 md = \frac{340 \times 0.4}{2} = 68\text{ m}
Multiplying the speed by half the elapsed time gives the distance to the wall.

Key Concept

Echo distance calculation
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