A proposed high-voltage transmission line connecting a hydro-electric station to an urban sub-station measures on a topographical map drawn to a scale of . If the map undergoes a photographic reduction such that its total surface area becomes of its original size, what is the actual ground distance, in kilometers, represented by a length of measured on the newly reduced map?
Answer: 5.8 km
Answer
The actual ground distance represented by 5.8 cm on the reduced map is 5.8 kilometers.
Reducing the surface area of a map to one-fourth reduces its linear dimensions to one-half, because linear scale factor equals the square root of the area scale factor. With linear dimensions halved, each centimeter on the new map represents twice as much ground distance as before, changing the scale from 1 : 50,000 to 1 : 100,000. At a scale of 1 : 100,000, 1 cm represents 1 km. Therefore, 5.8 cm on the reduced map corresponds to an actual ground distance of 5.8 km.
Step-by-Step Solution
Key Concept
Linear vs Area Scale Conversion and Ground Distance Calculation