Question

Difficulty: Very hardScalars and Vectors

Three coplanar forces act simultaneously at a point OO. The first force of magnitude 10 N10\text{ N} acts due East, and the second force of magnitude 10 N10\text{ N} acts at an angle of 6060^\circ North of East. If a third force keeps the system in static equilibrium, what is the magnitude of this third force?

  1. 103 N10\sqrt{3}\text{ N}Answer
  2. B
    20 N20\text{ N}
  3. C
    102 N10\sqrt{2}\text{ N}
  4. D
    10 N10\text{ N}

Answer

The magnitude of the third force required for equilibrium is 103 N10\sqrt{3}\text{ N}.
Resolving the forces along the horizontal (East) and vertical (North) axes gives components of 15 N15\text{ N} and 53 N5\sqrt{3}\text{ N} respectively. The magnitude of the resultant force is 152+(53)2=300=103 N\sqrt{15^2 + (5\sqrt{3})^2} = \sqrt{300} = 10\sqrt{3}\text{ N}. Since the third force balances the system, its magnitude must equal that of the resultant, which is 103 N10\sqrt{3}\text{ N}.

Step-by-Step Solution

1
Resolve the two given forces into horizontal (xx) and vertical (yy) Cartesian components.
F1x=10 NF_{1x} = 10\text{ N}, F1y=0 NF_{1y} = 0\text{ N}; F2x=10cos(60)=5 NF_{2x} = 10 \cos(60^\circ) = 5\text{ N}, F2y=10sin(60)=53 NF_{2y} = 10 \sin(60^\circ) = 5\sqrt{3}\text{ N}.
Vector addition requires breaking non-orthogonal vectors into perpendicular component directions.
2
Calculate the total horizontal (RxR_x) and vertical (RyR_y) components of the resultant of the first two forces.
Rx=10+5=15 NR_x = 10 + 5 = 15\text{ N}, Ry=0+53=53 NR_y = 0 + 5\sqrt{3} = 5\sqrt{3}\text{ N}.
Adding aligned components yields the net component along each axis.
3
Compute the magnitude of the resultant force RR.
R=Rx2+Ry2=152+(53)2=225+75=300=103 NR = \sqrt{R_x^2 + R_y^2} = \sqrt{15^2 + (5\sqrt{3})^2} = \sqrt{225 + 75} = \sqrt{300} = 10\sqrt{3}\text{ N}.
Applying Pythagoras' theorem to orthogonal components determines the net magnitude.
4
Determine the magnitude of the equilibrant (third force).
Equibrant magnitude =R=103 N= R = 10\sqrt{3}\text{ N}.
For static equilibrium, the third force must be equal in magnitude and opposite in direction to the resultant of the first two forces.

Key Concept

Vector Addition and Equilibrium of Forces
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