Question

Difficulty: HardBinary Operations

A binary operation ∗\ast on the set of real numbers is defined by a∗b=a+b−2aba \ast b = a + b - 2ab. If (x∗3)∗2=38(x \ast 3) \ast 2 = 38, find the value of xx.

Answer: 3

Answer

The value of xx is 3.
Applying the binary operation definition sequentially yields x∗3=3−5xx \ast 3 = 3 - 5x for the inner expression, and (3−5x)∗2=15x−7(3 - 5x) \ast 2 = 15x - 7 for the composite expression. Equating 15x−7=3815x - 7 = 38 leads to 15x=4515x = 45, giving x=3x = 3.

Step-by-Step Solution

1
Evaluate the inner binary operation expression x∗3x \ast 3
x∗3=3−5xx \ast 3 = 3 - 5x
Apply the definition a∗b=a+b−2aba \ast b = a + b - 2ab with a=xa = x and b=3b = 3.
2
Evaluate the outer binary operation (3−5x)∗2(3 - 5x) \ast 2
(3−5x)∗2=15x−7(3 - 5x) \ast 2 = 15x - 7
Substitute the result from step 1 into the outer operation definition with a=3−5xa = 3 - 5x and b=2b = 2.
3
Set the resulting expression equal to 38 and solve the linear equation
x=3x = 3
Solve 15x−7=3815x - 7 = 38 by adding 7 to both sides to get 15x=4515x = 45, then dividing by 15.

Key Concept

Nested composition of defined binary operations
Rate this question