Question

Difficulty: Very hardIndices and Laws of Indices

Find the real value of xx that satisfies the exponential equation 4x3x12=3x+1222x14^x - 3^{x - \frac{1}{2}} = 3^{x + \frac{1}{2}} - 2^{2x - 1}.

Answer: 1.5

Answer

The value of xx is 1.51.5 (or 32\frac{3}{2}).
By using index laws to group base-2 terms on the left side and base-3 terms on the right side, we obtain 22x(32)=3x(43)2^{2x}\left(\frac{3}{2}\right) = 3^x\left(\frac{4}{\sqrt{3}}\right). Rearranging gives (43)x=833=(43)32\left(\frac{4}{3}\right)^x = \frac{8}{3\sqrt{3}} = \left(\frac{4}{3}\right)^{\frac{3}{2}}. Equating indices gives x=1.5x = 1.5.

Step-by-Step Solution

1
Group like exponential terms with base 2 and base 3 on opposite sides of the equation.
4x+22x1=3x+12+3x124^x + 2^{2x - 1} = 3^{x + \frac{1}{2}} + 3^{x - \frac{1}{2}}
Grouping terms with common prime bases allows for factoring exponential terms.
2
Apply the product and power laws of indices: 4x=22x4^x = 2^{2x}, 22x1=2122x2^{2x-1} = 2^{-1} \cdot 2^{2x}, 3x±12=3x3±123^{x \pm \frac{1}{2}} = 3^x \cdot 3^{\pm \frac{1}{2}}.
22x+1222x=3x3+3x132^{2x} + \frac{1}{2} \cdot 2^{2x} = 3^x \cdot \sqrt{3} + 3^x \cdot \frac{1}{\sqrt{3}}
Separating the variable exponents from constant exponents prepares each side for factoring.
3
Factor out 22x2^{2x} from the left side and 3x3^x from the right side, then simplify arithmetic terms.
22x(32)=3x(43)2^{2x}\left(\frac{3}{2}\right) = 3^x\left(\frac{4}{\sqrt{3}}\right)
Factoring isolates the variable terms 22x2^{2x} and 3x3^x from numerical constants.
4
Divide to form the ratio 4x3x=(43)x\frac{4^x}{3^x} = \left(\frac{4}{3}\right)^x and simplify the numerical fraction on the right.
(43)x=833\left(\frac{4}{3}\right)^x = \frac{8}{3\sqrt{3}}
Expressing both sides with unified variable bases facilitates solving for xx by equating powers.
5
Rewrite 833\frac{8}{3\sqrt{3}} as a power of 43\frac{4}{3} and solve for xx.
(43)x=(43)32    x=32=1.5\left(\frac{4}{3}\right)^x = \left(\frac{4}{3}\right)^{\frac{3}{2}} \implies x = \frac{3}{2} = 1.5
Since 833=43/233/2=(43)3/2\frac{8}{3\sqrt{3}} = \frac{4^{3/2}}{3^{3/2}} = (\frac{4}{3})^{3/2}, equating exponents yields x=1.5x = 1.5.

Key Concept

Solving mixed-base exponential equations by grouping, factoring, and converting to a unified base ratio.
Estimated Time:3m 0s
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